A. Factor the numerator as a difference of squares:

c. As

, the contribution of the terms of degree less than 2 becomes negligible, which means we can write

e. Let's first rewrite the root terms with rational exponents:
![\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bx%5Cto1%7D%5Cfrac%7B%5Csqrt%5B3%5Dx-x%7D%7B%5Csqrt%20x-x%7D%3D%5Clim_%7Bx%5Cto1%7D%5Cfrac%7Bx%5E%7B1%2F3%7D-x%7D%7Bx%5E%7B1%2F2%7D-x%7D)
Next we rationalize the numerator and denominator. We do so by recalling


In particular,


so we have

For

and

, we can simplify the first term:

So our limit becomes
Answer:
x is less than or equal to 9
which is x ≤ 9
Step-by-step explanation:
<span><u><em>Answer:</em></u>
247,000
<u><em>Explanation:</em></u>
To round a number to the nearest thousand, we check the digit in the <u>hundreds position</u>:
1- If the digit is <u>less than 5</u>, then we round down. This means that we simply convert all digits after the thousands to zero and that's it
2- If the digit is <u>equal to or more than 5</u>, then we round up. This means that we add one to the thousands digit and then convert all digits after the thousands to zero.
In the given number 247039, the number in the hundreds position is 0. This means that we will <u>round down
</u>
Therefore, 246039 rounded to the nearest thousand would simply give 247000
Hope this helps :)</span>
Answer:
It is the first answer choice.
Step-by-step explanation.
Use synthetic division and there is no remainder, so -1 is a factor