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Hitman42 [59]
3 years ago
9

I'm stuck on algebra.

Mathematics
2 answers:
Rainbow [258]3 years ago
7 0
Point slope form : y-y1 = m(x-x1)
slope intercept form : m=(y-y1)/(x-x1)
standard form : Ax + By = C

just pick any random points on a graph and plug the same points into all three forms.
lapo4ka [179]3 years ago
7 0

Algebra is tougher when they make you make up your own problems like this.

Point slope form: That's a line through point (a,b) with slope m,

y - b = m(x-a)

Let's pick point (2,-3) and slope 7,

y + 3 = 7(x-2)

Slope-intercept form: That's a line given slope m and y intercept b,

y = mx + b

We'll pick slope m=3 and y intercept -2:

y = 3x - 2

Standard form: That's ax+by=c or sometimes ax+by+c=0; standard form isn't standard. We'll go with the former, picking some random numbers for a,b,c;

4x - 3y = 5

Let's write all three equations in all three forms

y + 3 = 7(x-2) point/slope

y = 7x - 14 - 3

y = 7x - 17 slope/intercept

7x - y = 17 standard

~~~~~~~~~~

y = 3x - 2 slope/intercept

y + 2 = 3x point/slope

3x - y = 2 standard

~~~~~~~~~~~~~~~

4x - 3y = 5 standard

3y = 4x - 5

y = (4/3) x - (5/3) slope/intercept

y + 5/3 = (4/3) x point/slope

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            =\dfrac{\dfrac{\sqrt 3 (1 + e^{2x})}{2\sqrt x} -2e^{2x} \sqrt{3x}}{(1+e^{2x})^2}\\\\\\=\dfrac{\tfrac{\sqrt 3(1 +e^{2x}) - 4x\sqrt 3 e^{2x}}{2\sqrt x}}{(1+e^{2x})^2}\\\\\\=\dfrac{\sqrt 3(1+e^{2x} -4xe^{2x})}{2\sqrt x(1 +e^{2x})^2}

7 0
1 year ago
20. A rectangle has an area of 45 cm². The length is one cm less than twice the width. Find the dimensions of
prohojiy [21]
Width = 5, length = 9

Area = length * width

length = (2 * width) - 1

sub equation for length

45 = (2w - 1) * w
45 = 2w^2 - w
2w^2 - w - 45 = 0
(2w - 9)(w - 5)
2w - 9 = 0
w = 9/2, l = 8 no

w -5 = 0
w = 5, l = 9 yes
7 0
2 years ago
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