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Hitman42 [59]
3 years ago
9

I'm stuck on algebra.

Mathematics
2 answers:
Rainbow [258]3 years ago
7 0
Point slope form : y-y1 = m(x-x1)
slope intercept form : m=(y-y1)/(x-x1)
standard form : Ax + By = C

just pick any random points on a graph and plug the same points into all three forms.
lapo4ka [179]3 years ago
7 0

Algebra is tougher when they make you make up your own problems like this.

Point slope form: That's a line through point (a,b) with slope m,

y - b = m(x-a)

Let's pick point (2,-3) and slope 7,

y + 3 = 7(x-2)

Slope-intercept form: That's a line given slope m and y intercept b,

y = mx + b

We'll pick slope m=3 and y intercept -2:

y = 3x - 2

Standard form: That's ax+by=c or sometimes ax+by+c=0; standard form isn't standard. We'll go with the former, picking some random numbers for a,b,c;

4x - 3y = 5

Let's write all three equations in all three forms

y + 3 = 7(x-2) point/slope

y = 7x - 14 - 3

y = 7x - 17 slope/intercept

7x - y = 17 standard

~~~~~~~~~~

y = 3x - 2 slope/intercept

y + 2 = 3x point/slope

3x - y = 2 standard

~~~~~~~~~~~~~~~

4x - 3y = 5 standard

3y = 4x - 5

y = (4/3) x - (5/3) slope/intercept

y + 5/3 = (4/3) x point/slope

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We can take prime numbers so they don't have a common factor other than 1.

3, and 5.

So we have to list the multiples to find the LCM

3: 3, 6, 9, 12, 15, 18
5: 5, 10, 15, 20, 25

15 is the LCM of 3 and 5

So, you can notice that if two numbers, lets call them a and b, have no common factor, then a \times b is the LCM.

Hope that helped :)

6 0
3 years ago
The endpoints of are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of ?
Masteriza [31]

Answer:

(\frac{x_e+x_f}{2} , \frac{y_e+y_f}{2})

Step-by-step explanation:

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Whats the answer & how do I solve it ?
Veseljchak [2.6K]

Answer:

Area of rectangle = 225/2 or 112.5

Step-by-step explanation:

Given,

Consider a rectangle ABCD.

Let AC be a diagonal of rectangle of length   = 15

In triangle  ABC.

Sin 45° =height/hypotenuse   {SinФ = height / hypotenuse}

Here, hypotenuse = diagonal of rectangle ( i.e AC = 15)

And height is AB

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or sin 45° = AB / 15

or 1/√2 = AB /15

AB = 15/√2

Similarly we can find Base (i.e BC) using cosine.

Cos 45° = Base/Hypotenuse

Cos 45° = BC / AC

or  1/√2 = BC/15

BC = 15/√2

Hence we got length of rectangle , AB= 15/√2

And width of rectangle , BC = 15/√2

Therefore, area of rectangle = Length × Width

Area of rectangle = 15/√2  ×   15/√2  = 225/2

Hence, area of rectangle = 225/2 = 112.5

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3

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