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4 years ago

Write an equation for the line slope-intercept form

Mathematics

1 answer:

dsp734 years ago

6 0

Answer:

The equation in slope-intercept form is:

$y= 2x + 5$

Step-by-step explanation:

-First, look for a two points on a graph:

First point: $(-3,-1)$

Second Point: $(-2,1)$

-Since the line is pointing up, then its telling us that it's positive. So, to start from point $(-3,-1)$ to point $( -2,1)$ , you need to count how far distance between those two points by using rise over run:

$m = \frac{rise}{run}$

$m = \frac{2}{1}$

$m = 2$

-After you have found the slope, find the y-intercept.

-The definition for y-intercept, is a line that crosses the y-axis.

y-intercept: $5$

After you found both the slope and the y-intercept, use them for the slope-intercept form:

The slope-intercept form:

$y = mx + b$

(where $m$ represents the slope and $b$ represents the y-intercept).

-The equation in slope-intercept form:

$y= 2x + 5$

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What are the zeros of f(x) = x2 - 12x + 36?

topjm [15]

Answer:

c. x = 6 only

Step-by-step explanation:

In order to calculate the zeros of f(x), we need to set it equal to zero and find the corresponding values of x.

$x^{2}-12x+36=0$

Using the midterm breaking, we can split -12x into two such terms whose sum will be -12x and product will be 36x². These two terms are -6x and -6x

So, the above expression can be written as:

$x^2-6x-6x+36=0\\\\ x(x-6)-6(x-6)=0\\\\ (x-6)(x-6)=0\\\\ (x-6)^{2}=0\\\\ x-6=0\\\\ x=6$

This means, the zero of f(x) occurs at x = 6 only.

8 0

3 years ago

30 POINTS AVAILABLE

kherson [118]

Answer:

$\large\boxed{(x-2)^2+(y-1)^2=34}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

3 0

4 years ago

What’s bigger 1.30 or 1.3

Firdavs [7]

they are both the same

7 0

3 years ago

Find the measure of the missing angle

crimeas [40]

Answer:

g=118 degrees h=62 degrees

Step-by-step explanation:

So we can use some angle rules that I forget the name of to solve this.

Let's look at angle g first. We know that the opposite angle is 118 degrees. So that also means that g is going to be 118 degrees.

Since g is 118 degrees we can find h. The angle of a line is 180 degrees. This means that we can do 180-118 to find h. h=62 degrees.

We can do the same thing for k and m. Try doing what I did for g and h for those two. Comment if you need help.

5 0

3 years ago

Which of the following functions is equal to f(x)=csc(x-9pi)+2 ? Select 3 answers

VladimirAG [237]

B. f(x) = csc(x - pie ) + 2 = - csc(x) + 2

C. f(x) = - csc(x - 2pie) + 2 = - csc(x) + 2

F. f(x) = - sec(x - 9pie/2 ) + 2 = - sec( x - 4pie - pie/2 ) + 2

= - sec(x - pie/2) + 2 = - csc(x) + 2

3 0

3 years ago