50.4 is the answer!! You multiply 84 by 0.60!!
Answer:
174
Step-by-step explanation:
I simplified radical 6 as 2 and 3, so 2(2)(3) = 12.
Then I simplified radical 54 as 2, 3, 3, and 3, so 3(2)(3)(3)(3) = 162.
162 + 12 = 174.
(If this is the wrong answer I'm sorry...it's been a while since I took geometry/algebra. xD)
Answer:
The answer is
![x = \frac{ - 9 - \sqrt{41} }{10} \: \: \: , \: \: \: \: \: \frac{ - 9 + \sqrt{41} }{10} \\](https://tex.z-dn.net/?f=x%20%3D%20%20%20%5Cfrac%7B%20-%209%20-%20%20%5Csqrt%7B41%7D%20%7D%7B10%7D%20%20%5C%3A%20%20%5C%3A%20%20%20%5C%3A%20%2C%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%20%5Cfrac%7B%20-%209%20%2B%20%20%5Csqrt%7B41%7D%20%7D%7B10%7D%20%20%5C%5C%20)
Step-by-step explanation:
5x² + 9x + 2 = 0
Using the quadratic formula that's
![x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B%20-%20b%20%5Cpm%20%5Csqrt%7B%20%7Bb%7D%5E%7B2%7D%20%20-%204ac%7D%20%7D%7B2a%7D%20%20%5C%5C%20)
From the question
a = 5 , b = 9 , c = 2
We have
![x = \frac{ - 9 \pm \sqrt{ {9}^{2} - 4(5)(2) } }{2(5)} \\ = \frac{ - 9 \pm \sqrt{81 -40 } }{10} \\ = \frac{ - 9 \pm \sqrt{41} }{10} \: \: \: \: \: \: \: \: \: \:](https://tex.z-dn.net/?f=x%20%3D%20%20%20%5Cfrac%7B%20-%209%20%5Cpm%20%5Csqrt%7B%20%7B9%7D%5E%7B2%7D%20-%204%285%29%282%29%20%7D%20%7D%7B2%285%29%7D%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B%20-%209%20%5Cpm%20%5Csqrt%7B81%20-40%20%7D%20%7D%7B10%7D%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B%20-%209%20%5Cpm%20%5Csqrt%7B41%7D%20%7D%7B10%7D%20%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20)
We have the final answer as
![x = \frac{ - 9 - \sqrt{41} }{10} \: \: \: , \: \: \: \: \: \frac{ - 9 + \sqrt{41} }{10} \\](https://tex.z-dn.net/?f=x%20%3D%20%20%20%5Cfrac%7B%20-%209%20-%20%20%5Csqrt%7B41%7D%20%7D%7B10%7D%20%20%5C%3A%20%20%5C%3A%20%20%20%5C%3A%20%2C%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%20%5Cfrac%7B%20-%209%20%2B%20%20%5Csqrt%7B41%7D%20%7D%7B10%7D%20%20%5C%5C%20)
Hope this helps you
Area of a circle is pi times the radius squared.
So, 1809.
Suppose that the universal set is U = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 }. Express each of these sets with bit strings, where the
Reika [66]
Answer:
a.0011100000
b.1010010001
c.0111001110
Step-by-step explanation:
We are given that a universal set
U={1,2,3,4,5,...10}
We have to express each given set with bit strings , where the ith bit in the string is 1 if i is in the set and 0 otherwise
a.{3,4,5}
For 1=0 because 1 is not in the given set
For 3=1, For 4=2 , For 5=1 because 3,4 and 5 are in the set
For 2=0
For 6=0
For 7=0
For 8=0
For 9=0
For 10=0
Therefore, bit string=0011100000
b.{1,3,6,10}
For 1,3,6 and 10 write 1 because these elements are present in the set and for 2,4,5,7,8,9 write 0 because these elements are not present in the set
Bit string =1010010001
c.{2,3,4,7,8,9}
Similarly
Those elements which are present in the set then for those elements write 1 otherwise 0.
Bit string =0111001110