Question

Let Z be a standard normal variable. Find the value of z if z satisfies P(Z > z) = 0.6331.

Answer 1

Answer:

$z = -0.340$

Step-by-step explanation:

We are given that Z is a standard normal variable.

We have to find the value of z such that

P(Z > z) = 0.6331

$P( Z > z)=0.6331$  

$= 1 -P( Z \leq z)=0.6331$  

$=P( Z \leq z)=1 - 0.6331 = 0.3669$  

Calculation the value from standard normal z table, we have,

$P(z \leq -0.340) = 0.3669$

Thus,

$z = -0.340$