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Jet001 [13]
3 years ago
14

4. 7 + 14x What does that mean

Mathematics
2 answers:
kotegsom [21]3 years ago
8 0

7 + 14x means that a number x (x could be any real number) times 14 is added to 7.

So if x = 2:

7 + 14x = 7 + 14(2) = 28 + 7 = 35

Happy to help!

VashaNatasha [74]3 years ago
4 0

Answer:x=2

Step-by-step explanation:

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Can I please get the answer?
Lyrx [107]

Answer:

24x+10y≥200

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Solve for X<br> 6x+60x+150=0
hammer [34]

Answer:

<h2><u><em>x = -2.27272727273</em></u></h2><h2><u><em>in fraction</em></u></h2><h2><u><em>x = -25/11</em></u></h2>

<u><em></em></u>

Step-by-step explanation:

Solve for X

6x+60x+150=0

66x = -150

x = -150 : 66

<u><em>x = -2.27272727273</em></u>

<u><em>in fraction</em></u>

<u><em>x = -25/11</em></u>

3 0
1 year ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.
sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then  

\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

\bf G(x,y) = (x, y, 3-x^2-y^2)

with 0≤ x≤1 and  0≤ y≤1

So

\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)

we also have

\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)

and so

\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and  0≤ y≤1

\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0
3 years ago
√20/125 answer in simpleset form<br>​
grigory [225]

Answer:

.4!

Step-by-step explanation:

first you divide 20 by 125 and get .16

then you take the square root of .16 and get .4

4 0
3 years ago
The sum of two times a number and four
Leokris [45]
Twice the sum of a number and 4 is 14. In this case the numbers are added first, and the ANSWER is doubled.
8 0
3 years ago
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