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Yuri [45]
4 years ago
15

If Michael's family has 210 acres And each cow takes 1/3 acre for grazing how many cattle could there farmland support

Mathematics
2 answers:
Pani-rosa [81]4 years ago
7 0

the answer for the quiz is 630 cows

Anna71 [15]4 years ago
4 0

Answer:

630

Step-by-step explanation:

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ANSWER PLS URGENT VERY URGENT TYSM ik its a lot of questions but id really really be grateful for the help
anyanavicka [17]

Step-by-step explanation:

about circle R

arc angle MP = angle MRP = 78°

angle M = angle LMP.

according to the rules of inscribed angles, LMP is half of angle LRP.

LRP + MRP = 180° because together they cover the whole LM segment (half-circle).

LRP = 180 - MRP = 180 - 78 = 102°

so, LMP = angle M = 102/2 = 61°

also circle R (with arc ULNP)

the arc ULNP = arc UL + arc LN + arc NP = 160°

due to the congruent definition of JU and MP we know that arc UL = arc NP.

and we know arc LN = arc JM = 18°.

so,

160 = 2×arc NP + 18

142 = 2×arc NP

arc NP = 71° = arc UL

now, because arc MP + arc LP = 180 (half-circle),

arc MP = 180 - arc LP = 180 - arc LN - arc NP =

= 180 - 18 - 71 = 91°

about the circle R with 2 congruent chords :

the second answer : they are equidistant from R (the center of the circle).

about circle W

arc MK + arc KL = 180° (half-circle).

and we see

arc HL = arc KL = 53°.

so,

arc MK + 53 = 180°

arc MK = 180 - 53 = 127°

about circle M

arc QTS = 204°.

therefore, arc QRS = 360 - arc QTS = 360 - 204 =

= 156° = angle QMS.

according to the rules of inscribed angles

angle QTS = QMS/2 = 156/2 = 78°

4 0
2 years ago
The radius of a circle is 6 yards. What is the circle's circumference? Use 3.14 for ​.
Orlov [11]

Answer:

18.84

Step-by-step explanation:

sorry if i get the wrong answer i literlly learn this but i complety forget it

5 0
3 years ago
Read 2 more answers
Find the flux of F = x^3 i  + y^3 j  + z^3k through the closed surface bounding the solid region x^2 + y^2 ≤ 4, 0 ≤ z ≤ 4
givi [52]
Use the divergence theorem. Let R be the cylindrical region, then

\displaystyle\iint_{\partial R}\mathbf F\cdot\mathbf n\,\mathrm dS=\iiint_R\nabla\cdot\mathbf F\,\mathrm dV

(where \mathbf n denotes the unit normal vector to \partial R, but we don't need to worry about it now)

We have

\mathrm{div }\mathbf F=(\nabla\cdot\mathbf F)(x,y,z)=\dfrac{\partial\mathbf F}{\partial x}+\dfrac{\partial\mathbf F}{\partial y}+\dfrac{\partial\mathbf F}{\partial z}
\nabla\cdot\mathbf F=3x^2+3y^2+3z^2

For the solid R with boundary \partial R, we can set up the following volume integral in cylindrical coordinates for ease:

\displaystyle3\iiint_R(x^2+y^2+z^2)\,\mathrm dV=3\int_{z=0}^{z=4}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}(r^2+z^2)r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz
=\displaystyle6\pi\int_{z=0}^{z=4}\int_{r=0}^{r=2}(r^3+rz^2)\,\mathrm dr\,\mathrm dz
=\displaystyle12\pi\int_{z=0}^{z=4}(2+z^2)\,\mathrm dz
=352\pi
5 0
3 years ago
The May 1, 2009, issue of a certain publication reported the following home sale amounts for a sample of homes in Alameda, CA th
MatroZZZ [7]
Noone does long answers lol
4 0
3 years ago
Triangle congruence and similarly (picture included) SAS, ASA, SSS, or AAS?
N76 [4]

Answer:

SAS

Step-by-step explanation:

SAS Postulate: "If two sets of corresponding sides on two triangles and there included angle are congruent, then the triangles are similar".

We see that line segments XY-ST and XZ-SR are congruent along with the included angles X and S. Therefore, we can justify that SAS fits the situation.

If this helped you, please consider giving a good rating, a thanks, and brainliest! It is greatly appreciated if you choose to do so! Thanks!

6 0
3 years ago
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