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3 years ago

Please help. Accuplacer question.

Mathematics

1 answer:

vampirchik [111]3 years ago

5 0

Answer:

D. 6

Step-by-step explanation:

The system can be solved by subtracting double the second equation from the first:

... (4x +3y) -2(2x +y) = (20) -2(7)

... y = 6 . . . . . . . . . for solution (x, y) = (a, b), this tells you b=6.

Putting this into the second equation gives ...

... 2x +6 = 7

... 2x = 1

... x = 1/2

The solution is (x, y) = (a, b) = (1/2, 6). b = 6.

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Joe ran 3 miles yesterday and wants to run at least 15 miles

igomit [66]

Answer: 3(x)≥15 →x≥5

Step-by-step explanation:

Set it up with x as the number of days. Then multiply that by 3, so that you get 3(x). This will show that for an x amount of days, you ran 3 miles. then set it to MORE THAN or EQUAL TO 15. Then divide both sides by 3, and you get the above answer.

4 0

3 years ago

PLEASE HELP ME. I NEED HELP

scoundrel [369]

#3). $124.16 will be in amount of deposit

#4) new balance, b = original balance + deposits - payments

=》 b =$782.14+$124.16 - ($450+$58.25)

=》 b = $398.05

3 0

4 years ago

A company introduced a much smaller variant of its tablet, known as the tablet junior. Weighing less than 11 ounces, it was abou

Inessa [10]

Answer:

0.2857

Step-by-step explanation:

Given that a company introduced a much smaller variant of its tablet, known as the tablet junior.

The weight was less than 11 oz. i.e. 50% lighter than std.

Let X be the battery life of the tablet junior

Then X is U(8.5,12)

Mean of X =10.25 hrs

the probability that the battery life for a tablet junior will be 9.5 hours or less

= $P(X\leq 9.5)\\=F(9.5)\\=\frac{9.5-8.5}{12-8.5} \\=0.2857$

7 0

3 years ago

(a^(?))/(a^(10))= a^(4) help me

UNO [17]

Answer:

a^? = 14

Step-by-step explanation:

a^? / a^10 = a^4

is also the same as

a^? - a^10 = a^4 ( due to laws of indices)

a^? = a^4 + a^10

a^? = a^14

the a's striking each other resulting in

? = 14

7 0

4 years ago

Given that x-1 and x+2 are factors of f(x)=x³+px+q where p and q are integers, find p and q. Hence, find the remainder when x³+p

alexandr1967 [171]

Answer:

p = -3
q = 2
remainder = 4

Step-by-step explanation:

We want to find the constants 'a', 'p', and 'q' such that ...

(x -a)(x -1)(x +2) ≡ x³ +px +q

(x -a)(x² +x -2) ≡ x³ +px +q

x³ +x² -2x -ax² -ax +2a ≡ x³ +px +q

This gives rise to three equations:

1 -a = 0 . . . . coefficient of x²

-2 -a = p . . . coefficient of x

2a = q . . . . . constant

The first of these tells us a=1. Then, p=-3 and q=2.

The values of p and q are -3 and 2, respectively.

The remainder from division by (x+1) is the value of the cubic for x=-1. That value is ...

(-1)³ -3(-1) +2 = -1 +3 +2 = 4

The remainder from division by (x+1) is 4.

7 0

3 years ago