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vova2212 [387]
3 years ago
10

You have the numbers 1–24 written on slips of paper.If you choose one slip at random, what is the probability that you will not

select a number which is divisible by 3
Mathematics
2 answers:
LenKa [72]3 years ago
5 0

The answer should be 2/3 because if u simplify 16/24 u get 2/3.

ollegr [7]3 years ago
3 0
The numbers that are divisible by 3 are:

3, 6, 9, 12, 15, 18, 21, 24
that is 8 numbers divisible by 3

24-8=16 numbers NOT divisible by 3

so the probability of not picking a number divisible by 3 is 16/24


hope this helps and is right :)
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Answer:

1. option B is correct i.e., \frac{-3a^{7}b^3b^1}{15a^{2}}

2. option D is correct i.e., \frac{a^3b^4}{ab^2}.

3. option B is correct i.e.,  \frac{n^{10}}{16m^{6}}.

Step-by-step explanation:

1. Since the given equation is:

\frac{-3a^{-2}b^3}{15a^{-7}b^{-1}}

As we know that a^{-x}=\frac{1}{a^x}

So, the given equation can be represented as:

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2. Given equation is:

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3.  Given equation is:

(\frac{4mn}{m^{-2}n^6})^{-2}

by using the properties a^{-x}=\frac{1}{a^x},

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(\frac{4mn}{m^{-2}n^6})^{-2}

= (\frac{4n^1n^{-6}}{m^{-2}m^{-1}})^{-2}

= (\frac{4n^{1+(-6)}}{m^{-2+(-1)}})^{-2}

= (\frac{4n^{-5}}{m^{-3}})^{-2}

= \frac{4^{-2}n^{-5\times (-2)}}{m^{-3\times (-2)}}

= \frac{n^{10}}{16m^{6}}.

which is option B.

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