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KengaRu [80]
3 years ago
5

Points A and B lie on a circle centered at point O. If what is the ratio of the area of sector AOB to the area of the circle?

Mathematics
1 answer:
Nataly [62]3 years ago
7 0

Answer:

C. 1/20

Step-by-step explanation:

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Given: ABCD is a kite
STatiana [176]
If angleb is 120 then AC is 120*2 = 240. 360-240 = 120 , 120/2 = 60 . If AB = 60 , angle adb is 30 and angle bdc is 30. DB is 2 * radius because angleA is 90. So with Pisagor AB = 3 , BC = 3 , AD = 3root3 and DC is 3root3.

Answer is = 6+6root3 = 6(1 + root3)




7 0
3 years ago
Use the substitution method to solve the system of equations. Choose the correct ordered pair.
Gnom [1K]

Answer:

i would say b

Step-by-step explanation:

6 0
3 years ago
A charity receives 2025 contributions. Contributions are assumed to be mutually independent and identically distributed with mea
uysha [10]

Answer:

The 90th percentile for the distribution of the total contributions is $6,342,525.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums of size n, the mean is \mu*n and the standard deviation is s = \sqrt{n}*\sigma

In this question:

n = 2025, \mu = 3125*2025 = 6328125, \sigma = \sqrt{2025}*250 = 11250

The 90th percentile for the distribution of the total contributions

This is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

1.28 = \frac{X - 6328125}{11250}

X - 6328125 = 1.28*11250

X = 6342525

The 90th percentile for the distribution of the total contributions is $6,342,525.

3 0
2 years ago
Melissa asked 10 students how many courses they have taken so far at her college. Here is the list of answers.
almond37 [142]

Answer:

Step-by-step explanation:

The question has asked who has taken fewer than 15 courses

There are 4 options that are fewer than 15: 10, 8, 8, 13

4/10  (10 is total number of options/students)

To find the percentage you...

6 0
2 years ago
A map's key shows that every 5 inches on the map represents 200 miles of actual distance Suppose the distance is 7 inches. What
zepelin [54]
280 mi
1 in= 40 mi

40x7=280 mi
8 0
3 years ago
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