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melamori03 [73]
3 years ago
12

What is the length of CD?

Mathematics
2 answers:
Mice21 [21]3 years ago
8 0
5 units so the last option
Ymorist [56]3 years ago
4 0
The length of CD is 5 units
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The lengths of two sides of a right triangle are 12 inches and 15 inches. What is the difference between the two possible length
Mademuasel [1]

Answer:

10.2 inches

Step-by-step explanation:

we know that

In this problem we have two cases

First case

The given lengths are two legs of the right triangle

so

a=12\ in, b=15\ in

Applying the Pythagoras Theorem

Find the length of the hypotenuse

c^{2}=a^{2} +b^{2}

substitute

c^{2}=12^{2} +15^{2}

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Second case

The given lengths are one leg and the hypotenuse

so

a=12\ in, c=15\ in

Applying the Pythagoras Theorem

Find the length of the other leg

b^{2}=c^{2} - a^{2}

substitute

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19.2-9=10.2\ in

3 0
4 years ago
Read 2 more answers
Partial products of 56×31
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You start by putting the numbers up and down like this
56
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On top of the 5 at the bottom you put 2 ones on top because 5+8 is 13 hope this helps
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some large frames for $14 each and some small frames for $4 each at a closeout sale. If she bought 16 frames for $114, find how
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Answer:

11 small frames, 5 large frames

Step-by-step explanation:

small: x

large : y

x + y = 16

4x + 14y = 114

Multiply first equation by 4 and subtract.

4x + 4y = 64

-(4x + 14y = 114)

-10y = -50

y = 5

Substitute y into the first equation.

x + 5 = 16

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3 years ago
58% of U.S adults have very little confidence in newspapers. You randomly select 10 U.S adults find the probability that the num
Greeley [361]
............................ 5.8
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4 years ago
Với điều kiện nào của m thì phương trình ( 3m^2 - 4) x -1=m-x có nghiệm duy nhất?
Shtirlitz [24]
 <span>a, để pt có nghiệm thì denta ≥ 0 <=> (3-m)^2 - 4( 3-2m) ≥ 0 <=> m^2 +2m-3 ≥ 0 ( ^ là mũ) 
giải bpt mới tìm được đó ta đc : m ≤ -3 hoặc m ≥ 1 
b, * Xét m-1=0 <=> m=1 => thay m=1 vào pt thì pt có 1 nghiệm là 1/8 (1) 
* Xét m-1 ≠ 0 <=> m ≠ 1 
=> pt có nghiệm khi denta' ≥ <=> (m+3)^2 - (m-1)(-m+2) ≥0 <=> 2m^2 +3m+11 ≥ 0 (*) 
-> bpt (*) có denta < 0 nên nó luôn đúng với mọi m ≠1 -> denta của pt đã cho luôn > 0 với mọi m ≠ 1 (2) 
từ (1) (2) => với mọi m pt luôn có nghiệm </span>
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