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Feliz [49]
4 years ago
9

can anyone help me with these? I'm having a lot of trouble and I'm extremely behind... I need to catch up badly!!! i have been a

t the hospital and have missed a lot of work :( you can just answer a couple if you want...

Mathematics
1 answer:
TiliK225 [7]4 years ago
6 0

Answer:

Step-by-step explanation:

5 and 6 are the same, so I will do one of those and you can use the example to do the other one.  

Slope-intercept form is y = mx + b.  If we have 2 points and nothing else, we can use those 2 points in the slope formula to find the slope (the m value in the equation) and then plug that in with either one of the points to get the equation.  The slope formula is:

m=\frac{y_{2} -y_{1} }{x_{2}-x_{1}  }

Using our points in question 5:  (2, 4) (5, 4)

m=\frac{4-4}{5-2} =\frac{0}{3}=0 So m = 0.  Now pick a point and use it in the equation along with the m value to solve for b.  I will use (2, 4):

4 = 0(2)+b and

4 = 0 + b so

b = 4.  

Now we have m = 0 and b = 4 so we fill in the equation with that info:

y = 0x + 4 or simplifying,

y = 4

For question 7 they want the line parallel to y = 3x + 6 that goes through (-10, 2.5).  For a line to be parallel to another line, their slopes have to be identical.  The slope in y = 3x + 6 is 3.  So the slope of the "new" line is going to be 3 as well.  Now we will use that slope and the given point to solve for b, just like in #5:

2.5 = 3(-10) + b and

2.5 = -30 + b so

b = 32.5

Now we will fill in:

y = 3x + 32.5

For question 8 they want the line perpendicular to y = -4x - 2 that goes through (-16, -11).  For a line to be perpendicular to another line, their slopes have to be opposite reciprocals.  Opposite meaning the sign is opposite (positive becomes negative and negative becomes positive), and reciprocal meaning the fraction is flipped upside down.  The slope in our line is -4.  That means that the perpendicular slope is positive 1/4.  Using that along with our point, we will again solve for b:

-11=\frac{1}{4}(-16)+b which simplifies to

-11 = -4 + b so

b = -7

Now we fill in:

y=\frac{1}{4}x-7

For question 8, in order to find the line parallel to the given line, you need to know the slope.  In the form it is currently in, we do not know the slope.  We need to put it into slope-intercept form to find the slope, then we will proceeed as above.  If

x + 4y = 6, then

4y = -x + 6 and, dividing by 4,

y=-\frac{1}{4}x+\frac{3}{2}

(The 3/2 is reduced from 6/4)

Now we can see the slope is -1/4.  We use that along with the point (-8, 5) to solve for b:

5=(-\frac{1}{4})(-8)+b which simplifies to

5 = 2 + b so

b = 3

Now we fill in, keeping in mind that lines are parallel when they have the exact same slope:

y=-\frac{1}{4}x+3

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Answer:

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Step-by-step explanation:

The relation R is an equivalence if it is reflexive, symmetric and transitive.

The order to options required to show that R is an equivalence relation are;

((a, b), (a, b)) ∈ R since a·b = b·a

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If ((a, b), (c, d)) ∈ R then a·d = b·c, which gives c·b = d·a, then ((c, d), (a, b)) ∈ R

Therefore, R is symmetric

If ((c, d), (e, f)) ∈ R, and ((a, b), (c, d)) ∈ R therefore, c·f = d·e, and a·d = b·c

Multiplying gives, a·f·c·d = b·e·c·d, which gives, a·f = b·e, then ((a, b), (e, f)) ∈R

Therefore R is transitive

From the above proofs, the relation R is reflexive, symmetric, and transitive, therefore, R is an equivalent relation.

Reasons:

Prove that the relation R is reflexive

Reflexive property is a property is the property that a number has a value that it posses (it is equal to itself)

The given relation is ((a, b), (c, d)) ∈ R if and only if a·d = b·c

By multiplication property of equality; a·b = b·a

Therefore;

((a, b), (a, b)) ∈ R

The relation, R, is reflexive.

Prove that the relation, R, is symmetric

Given that if ((a, b), (c, d)) ∈ R then we have, a·d = b·c

Therefore, c·b = d·a implies ((c, d), (a, b)) ∈ R

((a, b), (c, d)) and ((c, d), (a, b)) are symmetric.

Therefore, the relation, R, is symmetric.

Prove that R is transitive

Symbolically, transitive property is as follows; If x = y, and y = z, then x = z

From the given relation, ((a, b), (c, d)) ∈ R, then a·d = b·c

Therefore, ((c, d), (e, f)) ∈ R, then c·f = d·e

By multiplication, a·d × c·f = b·c × d·e

a·d·c·f = b·c·d·e

Therefore;

a·f·c·d = b·e·c·d

a·f = b·e

Which gives;

((a, b), (e, f)) ∈ R, therefore, the relation, R, is transitive.

Therefore;

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Based on a similar question posted online, it is required to rank the given options in the order to show that R is an equivalence relation.

Learn more about equivalent relations here:

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Answer: i think the answer is (A)

Step-by-step explanation:

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