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tigry1 [53]
2 years ago
9

Please help I did not get what I was supposed to do

Mathematics
2 answers:
Sladkaya [172]2 years ago
8 0

Answer:

See below

Step-by-step explanation:

\sqrt[3]{49}  = 3.65930571002 \approx3.66 \\  \\ so \:  \sqrt[3]{49} should \: lie \: at \: 3.6 \: which \:  \\ fall \: between \: 3 \: and \: 4.

Actually Lin did a mistake, she obtained square root and not cube root.

spayn [35]2 years ago
8 0

Answer with Explanation:

  • 3\sqrt{49} should be placed<u> in-between 3 and 4</u> on the number line (a little bit approaching number 4). The cube root of 49 is 6.66. Therefore, <em>it shouldn't be placed on number 7.</em>

  • Lin thought that she was asked to get the<em> square root of 49</em>, which looks like this: \sqrt{49}. Probably, she missed the number 3. It was actually asking for the<em> cube root of 49</em>. This is also the reason why she placed the dot on the number 7 because the<em> square root of 49 is 7</em>.

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