Please help I did not get what I was supposed to do

Mathematics

2 answers:

Sladkaya [172]2 years ago

8 0

Answer:

See below

Step-by-step explanation:

$\sqrt[3]{49} = 3.65930571002 \approx3.66 \\ \\ so \: \sqrt[3]{49} should \: lie \: at \: 3.6 \: which \: \\ fall \: between \: 3 \: and \: 4.$

Actually Lin did a mistake, she obtained square root and not cube root.

spayn [35]2 years ago

8 0

Answer with Explanation:

$3\sqrt{49}$ should be placed in-between 3 and 4 on the number line (a little bit approaching number 4). The cube root of 49 is 6.66. Therefore, it shouldn't be placed on number 7.

Lin thought that she was asked to get the square root of 49, which looks like this: $\sqrt{49}$ . Probably, she missed the number 3. It was actually asking for the cube root of 49. This is also the reason why she placed the dot on the number 7 because the square root of 49 is 7.

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What is the equation of the line that passes through the points (-1, 1.5) and (0.5, 0.5)

Step2247 [10]

The slope-point formula:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have:

$(-1,\ 1.5)\to x_1=-1,\ y_1=1.5\\(0.5,\ 0.5)\to x_2=0.5,\ y_2=0.5$

Substitute:

$m=\dfrac{0.5-1.5}{0.5-(-1)}=\dfrac{-1}{1.5}=-\dfrac{1}{\frac{3}{2}}=-\dfrac{2}{3}\\\\y-1.5=-\dfrac{2}{3}(x-(-1))\\\\y-1.5=-\dfrac{2}{3}x-\dfrac{2}{3}\\\\y-\dfrac{3}{2}=-\dfrac{2}{3}x-\dfrac{2}{3}\ \ \ |+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2}{3}+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2\cdot2}{3\cdot2}+\dfrac{3\cdot3}{2\cdot3}\\\\y=-\dfrac{2}{3}x-\dfrac{4}{6}+\dfrac{9}{6}\\\\y=-\dfrac{2}{3}x+\dfrac{5}{6}$