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tigry1 [53]
3 years ago
12

What is the distance of the two endpoints (3, 5) and (-6, -6)?

Mathematics
1 answer:
Jet001 [13]3 years ago
3 0

Distance = sqrt(5- -6)^2 + (3- -6)^2)

= sqrt (121 + 81)

= sqrt 202

= 14.21 to nearest hundredth

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Step-by-step explanation:

Parallel lines have identical slopes and different y intercepts.

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Georgia ran a 5-kilometer race. How many meters did she run?
kumpel [21]

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bonufazy [111]
<span>26.5 the way it is written but it could be asking for multiplication?</span>
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A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9
geniusboy [140]

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Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of 6.6 km and 3.9 km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, a^{2}+b^{2} =c^{2}, where a and b are the lengths of the triangle's legs and c is the length of the triangle's hypotenuse. In this case, we know what a and b are, and we need to solve for c, so after substituting the given values of a and b into a^{2}+b^{2} =c^{2} to solve for c, we get:

a^{2}+b^{2} =c^{2}

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43.56+15.21=c^{2} (Evaluate the squares on the LHS)

58.77=c^{2} (Simplify the LHS)

c^{2}=58.77 (Symmetric Property of Equality)

\sqrt{c^{2} } =\sqrt{58.77} (Take the square root of both sides of the equation)

c=7.7,c=-7.7 (Simplify)

c=-7.7 is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately 7.7 km away from its base. Hope this helps!

7 0
3 years ago
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Masja [62]
A. correct as it is
B. 5, 4, 3, 0
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3 years ago
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