Equate real part and imaginary part:
LHS:
real part -- 12
imaginary part -- 5y
RHS:
real part = 4x
imaginary part = 25
Equating::
12 = 4x
x = 12/4
x = 3
Again:
5y = 25
y = 25/5
y = 5
So,
x = 3
y = 5
If you mean by a(t)=2t+9 is the acceleration function then we integrate...
v(t)=2t^2/2+9t+c where c is vo and we are told that that is -7 so
v(t)=t^2+9t-7 integrating again we get:
s(t)=t^3/3+9t^2/2-7t+c where c is the initial position which is 8 so
s(t)=t^3/3+9t^2/2-7t+8 which neatened up as
s(t)=(2t^3+27t^2-42t+48)/6
Brandon's backpack weighs = 3140 grams.
We know, 1000 grams in a kilogram.
Therefore, 3140 grams = 3000 grams + 140 grams = 3 kilogram 140 grams.
Brandon weighs(without backpack) = 22 kg 610 grams more than his backpack.
More than pharse represents addition.
22 kg 610 grams more than backpack weighs = 22 kg 610 grams + 3 Kg 140 = 25 Kg 750 grams.
Therefore, Brandon weighs(without backpack) = 25 Kg 750 grams.
Total weight of Brandon weighs and backpack weighs = Brandon weighs(without backpack) + backpack weighs.
= 25 Kg 750 grams + 3 Kg 140 grams
= 28 Kg 890 grams.
Therefore, Brandon got 28 Kg 890 grams on a scale when wearing his backpack.
For problem 1, the number classification problem,
Natural: 1
Whole: 0
Integer: -3
Rational: 6
Irrational: pi
When plotting pi, put it just in front of the number 3
Happy Holidays!
We can use the following equation to calculate uniform acceleration:
Plug in the given values to solve:
