Of means times
45%=.45
96X.45= 43.2
<h2>9 ft</h2>
Step-by-step explanation:
The height of kangaroo after it jumps is represented by the function 
, where 
is in seconds, height is in feet.
To find the maximum height that the kangaroo jumps, we need to maximise 
.
The minimum/maximum value of a quadratic expression 
is given by 
.
As the coeffecient of quadratic term is negative, the function has a maxima.
Maximum value = 
.
∴ Maximum height = 9 ft
Answer:
Hi there!
The answer to this question is c=23, b and d=157
this is because c is the vertical angle of a meaning the values are equal
and b is the supplementary angle to a: all you do is subtract 23 from 180 to get 157.
b is vertical to d, so d is also 157
The enclosed shape is that of a trapezoid. The area of a trapezoid is the product of the height of it (measured perpendicular to the parallel bases) and the average length of the two parallel bases. The formula is generally written ...
... A = (1/2)(b₁ + b₂)·h
Here, the base lengths are the y-coordinates at x=4 and x=9. The height is the distance between those two x-coordinates: 9 - 4 = 5.
You are expected to find the y-values at those two points, then use the formula for the area of the trapezoid.
You can save a little work if you realize that the average of the two base lengths is the y-coordinate corresponding to the average x-coordinate: (9+4)/2 = 6.5. That is you only need to find the y-coordinate for x=6.5 and do the area math as though you had a rectangle of that height and width 5.
Going that route, we have
... y = 2(6.5) - 1 = 13 - 1 = 12
Then the trapezoid's area is
... A = 12·5 = 60 . . . . square units.
THE ASNWER IS 0.9.
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