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densk [106]
3 years ago
13

Logb

Mathematics
2 answers:
Ronch [10]3 years ago
8 0

Answer:

1.511

Step-by-step explanation:

bekas [8.4K]3 years ago
7 0

Answer:

1st part: 1.511

2nd part: A

3rd part: C

Step-by-step explanation:

on edge

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Help PLSSSSSSSSSSSSSSSSS extra points
arlik [135]

Answer:

85 messages

Step-by-step explanation:

The system of equations for this is

35 + .10x

18 + .3x

where x = the number of text messages

Usually, you would use substitution or elimination to solve this problem. However, because the answer choices were given, you can just plug in the values.

When you plug in 85, or x = 85, you get 43.5 for both equations because

35 + .10(85) = 43.5     18 + .3(85) = 43.5

Therefore, the answer would be 85 messages becuase both plans will cost the same when you send 85 text messages!

:)

7 0
3 years ago
Sorry im not smart. will give brainliest
MakcuM [25]

Answer:

The answer is 161051

..........

8 0
3 years ago
Read 2 more answers
Urgent ASAP!! Imagine math
Paraphin [41]

Answer:

Graph A = 20miles/gallon

Graph B = 20

Step-by-step explanation:

For graph A, to find the change you will need to choose two points from the graph (the easier the better)

So for example, I've chosen 40miles-2gallons (2, 40) and point 0 (0, 0)

Now you will need to remember the slope formula which is:

m=\frac{y_2-y_1}{x_1-x_2}

so your point (x1, y1) will be (0, 0)

and point (x2, y2) will be (2, 40)

so m=\frac{40-0}{2-0}

which is m=\frac {40}{2} = 20

and so you get that the slope will be 20 miles/gallon

For graph B, what they want you to see is that change of y/change of x means the same as change of miles/change of gallons since x is the gallons and y is the miles.

8 0
3 years ago
Which is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)? y squared over 40 minus x square
N76 [4]

The equation of the hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0) is \frac{x^2}{10} + \frac{y^2}{15} = 1

<h3>How to determine the equation of the hyperbola?</h3>

The given parameters are:

  • Directrices at x = ±2
  • Foci at (5, 0) and (−5, 0)

The foci of a hyperbola are represented as:

Foci = (k ± c, h)

The center is:

Center = (h,k)

And the directrix is:

Directrix, x = h ± a²/c

By comparison, we have:

k ± c = ±5

h = 0

h ± a²/c = ±2

Substitute h = 0 in h ± a²/c = ±2

0 ± a²/c = ±2

This gives

a²/c = 2

Multiply both sides by c

a² = 2c

k ± c = ±5 means that:

k ± c = 0 ± 5

By comparison, we have:

k = 0 and c = 5

Substitute c = 5 in a² = 2c

a² = 2 * 5

a² = 10

Next, we calculate b using:

b² = c² - a²

This gives

b² = 5² - 10

Evaluate

b² = 15

The hyperbola is represented as:

\frac{(x - k)^2}{a^2} + \frac{(y - h)^2}{b^2} = 1

So, we have:

\frac{(x - 0)^2}{10} + \frac{(y - 0)^2}{15} = 1

Evaluate

\frac{x^2}{10} + \frac{y^2}{15} = 1

Hence, the equation of the hyperbola is \frac{x^2}{10} + \frac{y^2}{15} = 1

Read more about hyperbola at:

brainly.com/question/3405939

#SPJ1

6 0
2 years ago
Simplify<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20%7B5%7D%5E%7B4%7D%20%7D%20" id="TexFormula1" title=" \sqrt[
lukranit [14]

Answer:

5

Step-by-step explanation:

\sqrt[4]{ {5}^{4} } \\   =  ({5}^{4})^{ \frac{1}{4} }   \\  =  {5}^{ \frac{4}{4} }  \\  = 5

5 0
2 years ago
Read 2 more answers
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