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Lilit [14]
3 years ago
9

An architect's electronic blueprint of a building has a scale of 1 inch equals 12 feet. What's the actual distance between the f

loor on the first floor and the floor on the 15th floor if the blueprint shows that the two floors are 14.375 inches apart?
A. 171.6 feet
B. 172.8 feet
C. 172.44 feet
D. 172.5 feet
Mathematics
2 answers:
lbvjy [14]3 years ago
7 0

Answer:

Option D is correct choice.

Step-by-step explanation:

We are told that an architect's electronic blueprint of a building has a scale of 1 inch equals 12 feet.

To find actual distance between the floor on the first floor and the floor on the 15th floor we will multiply blueprint distance by 12.

14.375\text{ inches} \cdot 12\frac{\text{ feet}}{\text{ inch}}

=172.5\text{ feet}

Therefore, actual distance between the floor on the first floor and the floor on the 15th floor is 172.5 feet.

alekssr [168]3 years ago
4 0

Answer:

Option D. 172.5 feet.

Step-by-step explanation:

An architect's electronic blueprint of a building has a scale of 1 inch = 12 feet.

It is given that the distance between first floor and 15th floor = 14.375 inches.

We will make a set up of equal ratio.

\frac{\text{12 feet}}{\text{1 inches}} = \frac{\text{x feet}}{\text{14.375 inches}}

x = 14.375 × 12

x = 172.5 feet

Option D. The two floors are 172.5 feet apart.

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