Given:
Sample proportion = 85% = 0.85.
Confidence level (CL) = 90%.
Confidence interval (CI)

We want the confidence interval to be 5% or 0.05. Therefore

Because this number is less than 1, a default sample size of 30 (for the normal distribution) is recommended.
Answer: 30
I believe the 11/25 one would be 44% and 4/50 would be 8%, 4/5 would be 80%. Hope it helps!
Answer:
7m^2 - 11m - 2
Step-by-step explanation:
Subtract (-3m^2 + 10m + 4) from 4m^2 - m + 2:
4m^2 - m + 2
- (-3m^2 + 10m + 4) Now distribute the negative sign:
4m^2 - m + 2
+ 3m^2 - 10m - 4
--------------------------
7m^2 - 11m - 2 is the final answer.