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Alecsey [184]
3 years ago
12

In a bowl of fruit, there are green grapes and black grapes in the ratio of 3:4 in there are 24 green grapes, how maney balck gr

apes are there
Mathematics
2 answers:
jenyasd209 [6]3 years ago
8 0
For every 3 green grapes there are 4 black grapes.

There are 24 green grapes, which is 3*8, so there must be 4 * 8 = 32 black grapes.
Irina18 [472]3 years ago
8 0

Answer:

32

Step-by-step explanation:

Given: In a bowl of fruit, there are green grapes and black grapes in the ratio of 3:4 in there are 24 green grapes.

To Find: how many black grapes are there.

Solution:

The ratio of green grapes and black grapes is 3:4

Let the number of green grapes in bowl be =3\text{x}

Therefore

Number of black grapes are =4\text{x}

now,

Number of green grapes are =24

3\text{x}=24

\text{x}=8

Number of black grapes are =4\text{x}

                                               4\times8

                                               32

hence the total number of black grapes in bowl of fruit is 32.

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jarptica [38.1K]

Answer:

(a) 0.1414

(b) 0.1010

Step-by-step explanation:

(a)

The density curve is rectangular in shape.

This implies that the distribution of donations is Uniform.

(b)

Compute the probability of donations at least 85 cents as follows:

P(X\geq 85)=\int\limits^{99}_{85} {\frac{1}{99-0} \, dx

                 =\frac{1}{99}\times [x]^{99}_{85}\\\\=\frac{99-85}{99}\\\\=0.1414\\\\

Thus, the proportion of donations that are at least 85 cents is 0.1414.

(b)

Compute the probability of donations between 30 and 40 cents as follows:

P(30\leq X\leq 40)=\int\limits^{40}_{30} {\frac{1}{99-0}} \, dx

                         =\frac{1}{99}\times [x]^{40}_{30}\\\\=\frac{40-30}{99}\\\\=0.1010

Thus, the probability of donations between 30 and 40 cents is 0.1010.

7 0
4 years ago
I need help on 4, 5, 6, and 7 please
astraxan [27]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

<em>Answer:</em>

4) 0.875

5) 3.6

6) 2.67

7) 0.48

Those are your answers!

7 0
4 years ago
Read 2 more answers
David took his family out for dinner. He planned to leave a 20% gratuity on the bill. What is the total cost if the bill was $12
denis23 [38]
Let’s find 1% of 125 first.
125 x 0.01 = $1.25
1.25 x 20 = $25 gratuity.

Bill + gratuity = Total
$125 + $20 = $145

$145 is the answer.

Hope that helped! :)
4 0
3 years ago
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Henry went to an amusement park with $150.00 and spent all of it. He spent 1/5 of the money on parking He spent $37.00 on admiss
sashaice [31]

Answer:

8 games

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

Total amount = $150

Spent on Parking = 1/5 or 20% = $150 × 20% = $30

Spent on admission = $37

Spent on food = 40% = $150 × 40% = $60

Spent on admission in waterpark = $10

Each game cost = $1.5

So, let number of games played be X, then

$30 + $37 + $60 + $10 + $1.5X = $150

$137 + $1.5X = $150

1.5X = $150 - $137

1.5X = $13

X = $13 ÷ 1.5 = 8.67 or 8 games

Hence, Henry can play 8 games.

7 0
3 years ago
2. Bella's cell phone costs $18 per month plus $0.15 for every minute she uses the phone. Last month her bill was $29.25. For ho
Alex777 [14]
Hello! So in order to solve this problem, it's best to start off making an equation.    $18 + $.15x = $29.25  

In this equation x represents the number of minutes she used. So now, we just have to solve for x.

First subtract $18 from both sides. Your new equation will be $.15x = $11.25. Then divide both sides by $.15 to get x by itself. $11.25/$.15 = 75.

So we can conclude that Bella spoke on the phone for 75 minutes this last month. Hope this helps!
8 0
4 years ago
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