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4 years ago

Anthony purchased 4 burgers for 4.60. Based on this rate, how much would one burger cost?

Mathematics

2 answers:

chubhunter [2.5K]4 years ago

8 0

4.60 divided by the number of burgers, being 4, equalling one dollar and 15 cents

Vladimir [108]4 years ago

5 0

All you need to do is divide 4.60 by 4

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How do you solve square roots....plz give me some examples

mamaluj [8]

Square roots are numbers.
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8×8 is 64 :)

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3 years ago

And please help solve 16

olganol [36]

Answer:

There is a pattern in the x column; add 2.

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Step-by-step explanation:

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3 years ago

Five men and 5 women are ranked according to their scores on an examination. Assume that no two scores are alike and all 10! pos

m_a_m_a [10]

Answer:

$P(X=1)=\frac{1}{2}\\P(X=2)=\frac{5}{18}\\P(X=3)=\frac{5}{36}\\P(X=4)=\frac{5}{84}\\P(X=5)=\frac{5}{252}\\P(X=6)=\frac{1}{252} \\P(X>6)=0$

Step-by-step explanation:

Let's define the following event :

X : ''Highest ranking achieved by a woman''

There are five men and five women so the lowest ranking possible is 6, this means that all five men achieved a better ranking than all five women.

In terms of the variable :

X can assume the following values :

$X=1\\X=2\\X=3\\X=4\\X=5\\X=6$

⇒ $P(X=7)=0\\P(X=8)=0\\P(X=9)=0\\P(X=10)=0$

⇒ $P(X>6)=0$

Now let's calculate the probability function for X

$P(X=1)=\frac{(5)(9!)}{(10!)}=0.5=\frac{1}{2}$

We write on the denominator the total ways to arrange ten different persons in a line. This number is 10!

On the numerator we write the total cases in which the first person is a woman ⇒ (5).(9!)

Because they are five different women and when you pick one of then they are 9! ways to arrange the 9 remaining persons

Following this logic, we continue calculating the probability function :

$P(X=2)=\frac{(5)(5)(8!)}{(10!)}=\frac{5}{18}$

Again : Five different ways to choose between the five men in the first position.Then, 5 different ways to choose between the five women.And finally, 8! ways to arrange the remaining persons

$P(X=3)=\frac{(5)(4)(5)(7!)}{(10!)}=\frac{5}{36}$

Here we have : five different ways to choose between five men.Four different ways to choose between the four remaining men.Five different ways to choose between the five women for the third position and finally 7! ways to arrange the remaining persons.

$P(X=4)=\frac{(5)(4)(3)(5)(6!)}{(10!)}=\frac{5}{84}$

$P(X=5)=\frac{(5)(4)(3)(2)(5)(5!)}{(10!)}=\frac{5}{252}$

$P(X=6)=\frac{(5)(4)(3)(2)(1)(5)(4!)}{(10!)}=\frac{1}{252}$

3 0

3 years ago

stack of mail consists of 8 bills, 10 letters, and 6 advertisements. One piece of mail is drawn at random and put aside. Then a

kozerog [31]

INFORMATION:

We know that:

- stack of mail consists of 8 bills, 10 letters, and 6 advertisements.

- One piece of mail is drawn at random and put aside. Then a second piece of mail is drawn.

And we must find P (both are letters)

STEP BY STEP EXPLANATION:

To find the probability, we need to know that we have two events. First, when one piece of mail is drawn at random and put aside and, second, when a second piece of mail is drawn.

These two events are dependent. If A and B are dependent events, P(A and B) = P(A) • P(B after A) where P(B after A) is the probability that B occurs after A has occurred.

So, first

- Probability of A (the first piece is letter)