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nadezda [96]
2 years ago
8

-6x-7=3x+11 how to solve this problem

Mathematics
1 answer:
Shalnov [3]2 years ago
6 0
You have to get the x to one side so you'll subtract 3x from -6x and 3x from 3x, the 3x will cancel out and -6x - 3x is -9x-7=11, you have to add 7 from both sides the 7+7 cancels out  and also add 11+7 which leaves -9x=18, you have to divide -9x/-9 and do 18/-9, which gets you x=-2. Here's the work shown if you didn't what i said...
-6x-7=3x+11
-3x    -3x
-9x-7=11
    +7  +7
-9x=18
-9   -9
x=-2
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6 0
2 years ago
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For any quadratic equation ax² + bx + c = 0, the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

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3 years ago
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