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Rainbow [258]
3 years ago
7

How do you count in grams

Mathematics
1 answer:
Ahat [919]3 years ago
8 0
Here, hopefully this picture cane help

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4. A sports car accelerates from rest to a final velocity of 64 m/s at a rate of 12.3
Ivanshal [37]

Answer:

t = 5.2\ s

Step-by-step explanation:

Given

a= 12.3m/s^2 --- acceleration

v = 64m/s --- final velocity

u =0m/s --- initial velocity (it is 0, because the car starts from rest)

Required

Determine the time taken

This will be solved using Newton's first equation of motion:

v = u + at

Substitute values for v, u and a

64 = 0 + 12.3*t

64 = 12.3t

12.3t = 64

Make t the subject

t = \frac{64}{12.3}

t = 5.2\ s

<em>Hence, the time taken is approximately 5.2 seconds</em>

6 0
3 years ago
In the diagram below, BD &lt;-&gt; is parallel to XY&lt;-&gt; . What is the value of y?
Veronika [31]
Your answer would be A.83

8 0
4 years ago
Read 2 more answers
Which is the value of x?<br><br> a. x=3<br> b. x=6.5<br> c. x=8.5<br> d. x=14
Elodia [21]

Answer:

x = 14

Step-by-step explanation:

The angles form a straight line which makes them add to 180 degrees

4x+ 8x+12 =180

Combine like terms

12x+12 =180

Subtract 12 from each side

12x+12-12 = 180-12

12x=168

Divide each side by 12

12x/12 =168/12

x =14

4 0
3 years ago
The LATERAL Surface Area for the shape below is:
Anarel [89]

Answer:

Step-by-step explanation:

perimeter of Base=2(l+w)=2(11+10)=2×21=42 cm

lateral area =perimeter of Base×height=42×5=210 cm²

5 0
3 years ago
The graph of <img src="https://tex.z-dn.net/?f=y%20%3D%20ax%5E2%20%2B%20bx%20%2B%20c" id="TexFormula1" title="y = ax^2 + bx + c"
Reptile [31]

Answer:

(-b/2a, b^2/(4*a) - b^2/2a + c)

Step-by-step explanation:

For a general parabola:

y = a*x^2 + b*x + c

We can write the vertex as:

(h, k)

The x-value of the vertex is the value of the axis of symmetry.

Then we have:

h = x = -b/2a

Now we need to find the y-value of the vertex.

To do that, we just replace the variable "x" by the x-value of the vertex in our equation, so we get:

k = y = a*(-b/2a)^2 + b*(-b/2a) + c

k = b^2/(4*a) - b^2/2a + c

Then the coordinates of the vertex are:

(h, k) = (-b/2a, b^2/(4*a) - b^2/2a + c)

8 0
3 years ago
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