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Wittaler [7]
3 years ago
5

4. A sports car accelerates from rest to a final velocity of 64 m/s at a rate of 12.3

Mathematics
1 answer:
Ivanshal [37]3 years ago
6 0

Answer:

t = 5.2\ s

Step-by-step explanation:

Given

a= 12.3m/s^2 --- acceleration

v = 64m/s --- final velocity

u =0m/s --- initial velocity (it is 0, because the car starts from rest)

Required

Determine the time taken

This will be solved using Newton's first equation of motion:

v = u + at

Substitute values for v, u and a

64 = 0 + 12.3*t

64 = 12.3t

12.3t = 64

Make t the subject

t = \frac{64}{12.3}

t = 5.2\ s

<em>Hence, the time taken is approximately 5.2 seconds</em>

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