Question

4. A sports car accelerates from rest to a final velocity of 64 m/s at a rate of 12.3

Answer 1

Answer:

$t = 5.2\ s$

Step-by-step explanation:

Given

$a= 12.3m/s^2$ --- acceleration

$v = 64m/s$ --- final velocity

$u =0m/s$ --- initial velocity (it is 0, because the car starts from rest)

Required

Determine the time taken

This will be solved using Newton's first equation of motion:

$v = u + at$

Substitute values for v, u and a

$64 = 0 + 12.3*t$

$64 = 12.3t$

$12.3t = 64$

Make t the subject

$t = \frac{64}{12.3}$

$t = 5.2\ s$

Hence, the time taken is approximately 5.2 seconds