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Bond [772]
3 years ago
6

Three numbers whose sum is 57

Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0
50+5+2 or is there a certain type of number are you looking for?
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If I read a whole dictionary would you donate 1$ to see it?
Monica [59]

Answer:

I<em>t D</em>e<em>p</em>en<em>d</em>s

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6)<br> 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)
vlada-n [284]

1.

(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

2.

(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

3 0
2 years ago
If line n bisects segment CE, find the positive value of x.<br><br> A.6<br> B.10<br> C.15<br> D.9
givi [52]

9514 1404 393

Answer:

  D.  9

Step-by-step explanation:

The segment lengths are equal, so ...

  x^2 = 90-x

  x^2 +x -90 = 0 . . . . . . add x-90 to put in standard form

  (x +10)(x -9) = 0 . . . . . factor

The solutions are the values of x that make the factors zero: -10, 9.

The positive value of x is 9.

8 0
3 years ago
Read 2 more answers
What expression is equivalent to 486-9+6+3^*2
sattari [20]

Answer:

The expression equivalent to 486-9+6+3^*2 is 500-7+6+5^*2

Step-by-step explanation:

486-9+6+3^*2 = 500-7+6+5^*2

486-9+6+9 = 500-7+6+25

486-24 = 500-38

462 = 462

4 0
3 years ago
The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16
Sergio [31]

Answer:

We can conclude that the result is significant and production differ in cost variance.

Step-by-step explanation:

Given :

n1 = 16

n2 = 16

s1² = 5.7

s2² = 2.8

α = 0.10

H0 : σ1² = σ2²

H1 : σ1² ≠ σ2²

The test statistic :

Ftest = s1² / s2² =

Ftest = 5.7 / 2.8

Ftest = 2.036

Using the Pvalue from Fratio calculator :

df numerator = 16 - 1 = 15

df denominator = 16 - 1 = 15

Pvalue(2.036, 15, 15) = 0.0898

Pvalue = 0.0898

Since the Pvalue is < α ; We can conclude that the result is significant and production differ in cost variance.

3 0
3 years ago
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