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notsponge [240]
3 years ago
14

There are 6 girls and 7 boys in a class. A team of 10 players is to be selected from the class. What is the probability that a r

andomly chosen team has 3 or 4 girls?
Mathematics
2 answers:
shutvik [7]3 years ago
8 0
The sample space in the problem is 6 girls and 7 boys. If ten players are to be chosen composing of three or four girls, then
for 3 girls:6C3 * 7C7 / 13C 10 = 0.06993
for 4 girls: 6C4 * 7C6 / 13C 10 = 0.3671
we add the two and the answer is 0.4371 
deff fn [24]3 years ago
7 0

Answer:

answer 0.44

Step-by-step explanation:

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2 years ago
A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

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Step-by-step explanation:

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(x - 10.844) (x + 1.844)

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