Answer:
The probability that a truck drives between 86 and 125 miles in a day.
P(86≤ X≤125) = 0.5890 miles
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given mean of the Population = 100 miles per day</em>
<em>Given standard deviation of the Population = 23 miles per day</em>
<em>Let 'X' be the normal distribution</em>
<em>Let x₁ = 86</em>
<em /><em />
<em>Let x₂= 86</em>
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<u><em>Step(ii):</em></u><em>-</em>
<em> The probability that a truck drives between 86 and 125 miles in a day.</em>
<em>P(86≤ X≤125) = P(-0.61 ≤ Z≤ 1.08)</em>
<em> = P(Z≤ 1.08) - P(Z≤ -0.61)</em>
<em> = 0.5 +A(1.08) - ( 0.5 - A(-0.61)) </em>
<em> = A(1.08) + A(0.61) ( A(-Z)= A(Z)</em>
<em> = 0.3599 + 0.2291</em>
<em> = 0.5890</em>
<u><em>Conclusion:-</em></u>
The probability that a truck drives between 86 and 125 miles in a day.
P(86≤ X≤125) = 0.5890 miles per day