All categories

3 years ago

Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. Given = 3 square 2

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

8 0

As the Pythagoreans discovered to their horror, the sides of the isosceles right triangle are in ratio $1:1:\sqrt 2$ .

The hypotenuse is $\sqrt 2$ times the leg, so here is

$3 \sqrt{2} \times \sqrt{2} = 6$

Answer: 6

You might be interested in

Write a quadratic function in vertex form whose graph has the vertex (1, 0) and passes through the point (2, −17).

Brilliant_brown [7]

Answer:

x^4 +y+1

Step-by-step explanation:

6 0

3 years ago

Sara found that the older person is, fewer cartoons that person watches.

Misha Larkins [42]

Answer:

Step-by-step explanation:

The scatter graph shows a decreasing correlation.

Its not A because it's a increasing correlation

its not C because it's neutral

its not D because it's a no correlation graph

4 0

2 years ago

A company's revenue function and cost function are as follows: R(x) = 0.55x and C(x) = 10 + 0.05x. What is the minimum number of

Oduvanchick [21]

Answer:

Minimum number of units sold to make profit is equal to 20

Step-by-step explanation:

Revenue earned by the company as a function of number of units sold as x:

R(x) = 0.55x

Cost for selling units as a function of number of units sold as x:

C(x) = 10 + 0.05x

<em>Net profit earned by the company = (Revenue earned by the company) - (Cost of selling units)</em>

P(x) = (0.55x) - (10 + 0.05x)

P(x) = 0.55x - 10 - 0.05x

P(x) = 0.5x - 10

To earn profit the following condition should satisfy: P(x) ≥ 0

0.5x - 10 ≥ 0

0.5x ≥ 10

x ≥ $\frac{10}{0.5}$

x ≥ 20

4 0

3 years ago

Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2

Agata [3.3K]

$\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------$

$\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o$

8 0

3 years ago

Write the equation of the line that passes through (1, -2) and is parallel to x - 2y = -2.

DENIUS [597]

Answer:

y=(1/2)x-(5/2)

the slope is 1/2 so use that to find the equation of the line

7 0

2 years ago