D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, in ascending order
Q2 (median) = d5 = 2 //value in the middle
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 is middle value of d1,d2,d3,d4, but there is no middle element among four elements, that is why arithmetic mean is taken)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquantlie range = IQR = Q3 - Q1 = 5 -1 = 4
answer: 4

4 0

3 years ago

Read 2 more answers

3(x+2)=2(x+5) i really need help

Ivan

Answer:

x=4

Step-by-step explanation:

3(x+2)=2(x+5)

opening brackets

3x+6=2x+10

3x-2x=10-6

1x=4

6 0

4 years ago

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I need to evaluate <br> log base 3 (1/162)

Anni [7]

Log(a*b)=log(a)+log(b)
and
logₐbˣ=xlogₐb
also
x^-m=1/(x^m)
and
logₐaˣ=x

so
$log_3 \frac{1}{162}$ =y
$log_3 \frac{1}{2*3^4}$ =y
$log_3 \frac{1}{2} + log_3 \frac{1}{3^4}$ =y
$log_3 \frac{1}{2} + log_3 (3^{-4})$ =y
$log_3 \frac{1}{2} -4$ =y
the result is
$(log_3 \frac{1}{2})-4$

5 0

4 years ago