Ask question

Ask question

All categories

3 years ago

8

If a certain negative number is multiplied by six, the result is the same as 20 less than the original number. What is the value

of the original number?

1 answer:

Wittaler [7]3 years ago

5 0

let the number be X
6X=X-20
X+6X=20
-5X=20
X=-4

You might be interested in

K/4 - 5k + 1 = 1<br> please

irinina [24]

Answer:

-19k ≠ 0

No solutions

Step-by-step explanation:

k/4 - 5k + 1 = 1

4 (k/4 - 5k + 1 = 1)

k-20k + 4 = 4

-19k ≠ 0

4 0

3 years ago

Need help with this asap plz❤️

BigorU [14]

What question are you needed answers to?

6 0

3 years ago

Work out length of side b<br>give your answer to 1 decimal place<br><br>plzzzz hhheellpp

Vedmedyk [2.9K]

√b = 17.17 - 12.12

√b= 289 - 144

√b= 145

b= √145

3 0

3 years ago

Read 2 more answers

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

Sam made a password that consists of one letter followed by two digits. The two digits are different. How many possible password

slega [8]

Answer:

720

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers