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3 years ago

HERE IS A GOODNIGHT QUESTION :) - what’s something you hate?

Mathematics

2 answers:

nika2105 [10]3 years ago

8 0

Answer:

thanks for points

I hate mercy

hope it helps

weeeeeb [17]3 years ago

7 0

Answer:

For me is someone that feels you important and caring but in end she leave you for no reason

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The numbers 1 through 12 are written on 12 slips of paper, with a different number on each paper slip, and placed in a bag. One

Naddik [55]

If you're asking for the number of digits smaller than 13 in the bag:12

8 0

3 years ago

A 30ft electric line is suspended between the tops of two 20ft electric poles on level ground. The lowest point of the line is 5

Lilit [14]

Answer:

There is no distance between them

Step-by-step explanation:

For a 30 ft electric line to be placed between two 20ft electric poles, it would take 15 ft of the electric line to go down to about 5 ft above the ground and another 15 ft of the line to go to the top of the second electric pole. This means that a total of 30ft (15 ft + 15 ft) electric line would be needed which is all the cable we have.

For this to be possible then the poles must be adjacent to each other (i.e. no distance between them).

7 0

2 years ago

Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions

monitta

I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take $z=y'$ , so that $z'=y''$ and we're left with the ODE linear in $z$ :

$y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2$

Now suppose $y$ has a power series expansion

$y=\displaystyle\sum_{n\ge0}a_nx^n$
$\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}$
$\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}$

Then the ODE can be written as

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0$

$\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0$

$\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0$

All the coefficients of the series vanish, and setting $x=0$ in the power series forms for $y$ and $y'$ tell us that $y(0)=a_0$ and $y'(0)=a_1$ , so we get the recurrence

$\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}$

We can solve explicitly for $a_n$ quite easily:

$a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}$

and so on. Continuing in this way we end up with

$a_n=\dfrac{a_1}{n!}$

so that the solution to the ODE is

$y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x$

We also require the solution to satisfy $y(0)=a_0$ , which we can do easily by adding and subtracting a constant as needed:

$y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}$

4 0

3 years ago

Need help with math problem 5 stars and good rating if do

Tomtit [17]

Answer:

Bottom right

Explanation:

visualize both triangle connected to the middle rectangle, and that's a triangular prism

3 0

2 years ago

7 - 3b-2(0 + 3 - 2b)

Naddika [18.5K]

Step-by-step explanation:

7 - 3b-2(0 + 3 - 2b)

To simplify the expression in the box, Fatua used

these steps:

Step 1:7 - 3b-2(3 - 3b)

Step 2:7 - 3-6-36-

Step 3: -13 - 66

Did Fatua calculate correctly? if nnot, in what step

did she make her FIRST mistake?

6 0

2 years ago

Read 2 more answers