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Igoryamba
3 years ago
5

Use z scores to compare the given values. The tallest living man at one time had a height of 249 cm. The shortest living man at

that time had a height of 120.2 cm. Heights of men at that time had a mean of 176.55 cm and a standard deviation of 7.23 cm. Which of these two men had the height that was more​ extreme?
Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0

Answer:

Step-by-step explanation:

Average height = 176.55 cm

Height of tallest man = 249 cm

Standard deviation = 7.23

z score of tallest man

= (249 - 176.55) / 7.23

= 10.02

Average height = 176.55 cm

Height of shortest  man = 120.2 cm

Standard deviation = 7.23

z score of smallest  man

= ( 176.55 - 120.2 )  / 7.23

= 7.79

Since Z - score of tallest man is more , his height was more extreme .  

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Six times a number is greater than 20 more than that number. What are the possible values of that number?
seropon [69]
It would be easier to translate this into mathematical terms first.
Let n = the unknown number

6n <span>> n + 20

Subtracting both sides by n to simplify:
6n - n </span><span>> n + 20 - n
</span>5n <span>> 20
</span><span>
Dividing both sides by 5:
5n/5 </span><span>> 20/5
</span>n <span>> 4
</span><span>
Among the choices, the correct one is the second choice.

</span>
4 0
3 years ago
A driver's education course compared 1,500 students who had not taken the course with 1,850 students who had. Of those students
aivan3 [116]

Answer:

P-value is less than 0.999995 .

Step-by-step explanation:

We are given that a driver's education course compared 1,500 students who had not taken the course with 1,850 students who had.

Null Hypothesis, H_0 : p_1 = p_2 {means students who took the driver's education course and those who didn't took have same chances to pass the written driver's exam the first time}

Alternate Hypothesis, H_1 : p_1 > p_2 {means students who took the driver's education course were more likely to pass the written driver's exam the first time}

The test statistics used here will be two sample Binomial statistics i.e.;

                             \frac{(\hat p_1 - \hat p_2)-(p_1 - p_2)}{\sqrt{\frac{\hat p_1(1- \hat p_1)}{n_1} + \frac{\hat p_2(1- \hat p_2)}{n_2} } } ~ N(0,1)

Here, \hat p_1 = No. of students passed the exam ÷ No.of Students that had taken the course

 \hat p_1  = \frac{1150}{1850}            Similarly,  \hat p_2 = \frac{1440}{1500}          n_1 = 1,850       n_2 = 1,500

  Test Statistics = \frac{(\frac{1150}{1850} -\frac{1440}{1500})-0}{\sqrt{\frac{\frac{1150}{1850}(1- \frac{1150}{1850})}{1850} + \frac{\frac{1440}{1500}(1- \frac{1440}{1500})}{1500} } } = -27.38

P-value is given by, P(Z > -27.38) = 1 - P(Z > 27.38)

Now, in z table the highest critical value given is 4.4172 which corresponds to the probability value of 0.0005%. Since our test statistics is way higher than this so we can only say that the p-value for an appropriate hypothesis test is less than 0.999995 .

6 0
3 years ago
HELP ME I WILL GIVE BRANLISEST
RoseWind [281]

Answer:

i think it

Step-by-step explanation:

6 0
3 years ago
Help me solve for the right triangle
AleksAgata [21]

Answers:

B = 50

a = 10.9

c = 17.0

================================================

Explanation:

This is a right triangle, so the acute angles are complementary, meaning they add to 90

B+40 = 90

B+40-40 = 90-40

B = 50

Also, because this is a right triangle, we can use trig ratios to compute the missing sides

tan(angle) = opposite/adjacent

tan(40) = a/13

a = 13*tan(40)

a = 10.908

a = 10.9

cos(angle) = adjacent/hypotenuse

cos(40) = 13/c

c*cos(40) = 13

c = 13/cos(40)

c = 17.0

note: make sure your calculator is in degree mode

7 0
3 years ago
Can someone please help me with math.
Nat2105 [25]

Answer:

I think -3

Step-by-step explanation:

3 0
3 years ago
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