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2 years ago

Functions f(x) and g(x) are shown below:

Mathematics

1 answer:

Mashutka [201]2 years ago

6 0

The answer above is wrong.

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Factor the expression. d2 + 12d+ 36

Natali5045456 [20]

Answer:

the factored expression is

(d+6)(d+6) or (d+6)^2

Step-by-step explanation:

8 0

3 years ago

Consider the function f(x) = x^3 - 7x^2 - 2x + 14

mars1129 [50]

Answer:

There are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14$

To get the zeros of $f(x)$ , set $y$ or $f(x) =0$

$0=x^3-7x^2-2x+14$

$x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)$

$\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0$

Using the zero factor principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0$

solving

$x-7=0$

$x=7$

$x+\sqrt{2}=0$

$x=-\sqrt{2}$

$x-\sqrt{2}=0$

$x=\sqrt{2}$

Therefore, there are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

8 0

3 years ago

1. Classify the triangle according to side length and angle measurement.

mezya [45]

Answer:

1. Scalene right

2. Isosceles acute

3. Parallelogram

3 0

3 years ago

Read 2 more answers

The temperature at 9 p.m. was 12°F. The temperature dropped 15°F by 5 a.m.The temperature at 5 a.m. was

satela [25.4K]

The temperature at 5 am was -3 degrees

12-15=-3

4 0

2 years ago

WILL GIVE BRAINLIEST!!!!!

ruslelena [56]

Answer:

Step-by-step explanation:

m∠BCD = 145° ⇒ m∠BCA = 180° - 145° = 35°

From ΔABC:

m∠ABC + m∠BCA + m∠BAC = 180°

65° + 35° + m∠BAC = 180°

m∠BAC = 180° - 100°

m∠BAC = 80°

5 0

3 years ago