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Mars2501 [29]
3 years ago
6

The computer store pays its employees $150 per day plus a commission of 15% of their sales. Teagan wants to make at least $450 t

oday. Which equation will help Teagan determine how much he has to sell today? A. 0.15x + 150 ≥ 450 B. 150 – 0.15x ≥ 450 C. 450 – 0.15x ≥ 150 D. 0.15x – 450 ≥ 15
Mathematics
2 answers:
Savatey [412]3 years ago
6 0

The equation 0.15 x + 150 ≥ 450 will help Teagan determine how much he has to sell today ⇒ A

Step-by-step explanation:

The given is:

  • The computer store pays its employees $150 per day plus a commission of 15% of their sales
  • Teagan wants to make at least $450 today

We need to find which equation will help Teagan to determine how much he has to sell today

Assume that he has to sell by $x today

∵ The store pays $150 per day plus a commission of 15%

   of their sales

∵ Teagan's total sales = x

- Multiply 15% by x, then add the product by 150

∴ Teagan makes = 15% × x + 150

∵ 15% × x = \frac{15}{100} × x = 0.15 x

∴ Teagan makes = 0.15 x + 150

∵ Teagan wants to make at least $450 today

- At least means ≥

∴ Teagan makes ≥ 450

- Substitute Teagan makes by 0.15 x + 150

∴ 0.15 x + 150 ≥ 450

The equation 0.15 x + 150 ≥ 450 will help Teagan determine how much he has to sell today

Learn more:

You can learn more about the linear inequality in brainly.com/question/6703816

#LearnwithBrainly

Vinil7 [7]3 years ago
4 0

Answer:

you mean A

Step-by-step explanation:

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Answer:

y = (x-16)/7

Step-by-step explanation:

x - 7y = 16

~Subtract x to both sides

-7y = 16 - x

~Divide -7 to everything

y = (16-x)/7

Best of Luck!

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You put all the numbers on one side of the equation and letters on another. 

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6 0
3 years ago
The following data on average daily hotel room rate and amount spent on entertainment (The Wall Street Journal, August 18, 2011)
Zielflug [23.3K]

Answer:

a. Predicted Amount = $109.46

b. Confidence Interval = (94.84,124.08)

c. Interval = (110.6883,188.8517)

Step-by-step explanation:

Given

ŷ = 17.49 + 1.0334x.

SSE = 1541.4

a.

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

ŷ = 109.46 --- Approximated

Predicted Amount = $109.46

b.

ŷ = 17.49 + 1.0334(89)

ŷ = 109.4626

ŷ = 109.46

First we calculate the standard deviation

variance = SSE/(n-2)

v = 1541.4/(9-2)

v = 1541.4/7

v = 220.2

s = √v

s = √220.2

s = 14.839

Then we calculate mean(x) and ∑(x - (mean(x))²

X --- Y -- Mean(x) --- ∑(x - (mean(x))²

148 -- 161 -- 43-- 1849

96 || 105|| -9 || 81

91 ||101 || -14 || 196

110 || 142 || 5 || 25

90 || 100 || -15 || 225

102 || ||120 ||-3|| 9

136 || 167 ||31 ||961

90 || 140 ||-15 ||225

82 || 98 ||-23 || 529

Sum 945 || 1134|| 0 ||4100

Mean (x) = 945/9 = 105

∑(x - (mean(x))² = 4100

α = 1 - 95% = 5%

α/2 = 2.5% = 0.025

tα,df = n − 2 = t0.025,7 =2.365

Confidence interval = 109.46 ± 2.365 * 14.839 √((1/9)+ (89-105)²/4100

Confidence Interval = (109.46 ± 14.62)

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c.

ŷ = 17.49 + 1.0334(128)

ŷ = 149.7652

ŷ = 149.77

Interval = 149.77 ± 2.365 * 14.839 √((1/9)+ (128-105)²/4100

Interval = 149.77 ± 39.0817

Interval = (110.6883,188.8517)

3 0
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Answer: 128

Step-by-step explanation:

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