C and D
Hope this helps !
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
<span>
f(x)= −3/5x³</span><span>
The domain is all values x can be. There are no restrictions on x. it can be any real number (-∞ , ∞)
The range is all values y can be. There are noi restrictions on y either because the function is odd. y is </span><span>(-∞ , ∞)
The best answer is D.
domain (-∞, 0] ∪[0, ∞)
range </span><span>(-∞, 0] ∪[0, ∞) </span>
Answer:
$4000
Step-by-step explanation:
Given that :
Volume of cube = 8000 ft³
Charge per ft² = $10
Recall, volume of a cube = a³
Where a = edge
Hence,
a³ = 8000
Take the cube root of both sides
a = 20
Hence,
Volume = 20 * 20 * 20
The Area of the floor will be :
20 * 20 = 400 ft²
If charge per ft² = $10
400 ft² = ($10 * 400) = $4000
