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Firdavs [7]
3 years ago
6

Keith has $500 in a savings account to beginning of the summer he wants to have at least $200 at the end of the summer he withdr

aws 25 per week for the tickets how many weeks can Keith withdraw money from his account
Mathematics
2 answers:
jonny [76]3 years ago
8 0
12 weeks you just have to divide 300 and 25
IgorLugansk [536]3 years ago
5 0
The Answer is: 12 weeks
You just take 300/25 and you get the weeks
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Do you have to multiply?
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3 years ago
The center on a target has a diameter of 5 inches. The whole target has a diameter of 25 inches. Complete the explanation for wh
kicyunya [14]

Answer:

The center is \frac{1}{25} of the whole target.

Step-by-step explanation:

Given:

Diameter of the center = 5 inches

Diameter of the whole target = 25 inches

We need to find the part of the center to the whole target.

Solution,

Firstly we will find out the areas of center and whole target.

For center;

Diameter = 5 in

Radius of circle is equal to half of the diameter.

radius = \frac{diameter}{2}=\frac{5}{2}=2.5\ in

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = \pi \times{2.5}^2

For whole target;

Diameter = 25 in

Radius of circle is equal to half of the diameter.

radius = \frac{diameter}{2}=\frac{25}{2}=12.5\ in

Now we know that the area of circle is equal to π times square of the radius.

framing in equation form, we get;

Area = \pi \times12.5^2

Now to find the part of the center to the whole target we will divide Area of center with Area of the target.

framing in equation form we get;

the part of the center to the whole target = \frac{\pi \times2.5^2}{\pi \times12.5^2}= \frac{6.25}{156.25} = \frac{1}{25}

Hence the center is \frac{1}{25} of the whole target.

6 0
3 years ago
19. Find the current in a circuit if the power is 500 W (watts) and the resistance is 25 ohms. Round off your answer to two deci
HACTEHA [7]

Answer:

A

Step-by-step explanation:

The formula that relates current, power and resistance is

I=\sqrt{\frac{P}{R}}

Where

I is the current (in amperes)

P is the power (in watts)

R is the resistance (in ohms)

We know P = 500 and R = 25, we plug them into the formula and solve for I:

I=\sqrt{\frac{P}{R}}\\I=\sqrt{\frac{500}{25}}\\I=\sqrt{20}\\ I=4.47

Correct answer is 4.47 Amperes, or choice A.

4 0
3 years ago
Solve the system by substitution.<br> -8x – 7y = -5<br> -x = y
Lapatulllka [165]

Substitute y = -x into the first equation:

-8x - 7(-x) = -5

-8x + 7x = -5

-x = -5

x = 5

Substitute x = 5 into y = -x

y = -(5)

y = -5

Answer: x = 5, y = -5

6 0
3 years ago
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Mary has $135 to spend on clothes. She wants to purchase winter boots for $70 and some sweaters that cost $20 each. Write an ine
creativ13 [48]

Answer:

1 pair of boots and 6 sweaters

Step-by-step explanation:

70+20s = 135

-70             -70

20s = 135

divide 20 both sides

s = 6.75

She can buy 6 sweaters because she cannot buy half a sweater.

s - sweaters

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3 years ago
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