Step One
======
Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
hob
Step-by-step explanation:
jbibou
Answer:
Union forces staged a surprise attack but were forced to retreat.
Step-by-step explanation:
Answer:
Step-by-step explanation:
<h3>QUESTION-2:</h3>
we are given a right angle triangle
it's a 30-60-90 triangle of which FH is the shortest side
remember that,in case of 30-60-90 triangle the the longest side is twice as much as the shortest side thus
our equation is
divide both sides by 2
<h3>Question-1:</h3>
in order to figure out GH we can use Trigonometry because the given triangle is a right angle triangle
as we want to figure out GH we'll use sin function
remember that,
let our opp, hypo and 
be GH, 4√10 and 60° respectively
thus substitute:
recall unit circle:
cross multiplication:
simplify multiplication:
divide both sides by 2:
<h3>QUESTION-3:</h3>
Recall that, the sum of the interior angles of a triangle is 180°
therefore,
simplify addition:
cancel 150° from both sides
