Write an expression that represents 2 more than 4 times a number

2 answers:

4 0

Go backwards with the problem. 4 times a number would mean 4x. 2 more means you're adding 2. so your answer should be 4x+2

Anit [1.1K]2 years ago

3 0

6 more than 5 times a number
5x+6

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Please help I need you guys A farmer sells corn for $2 per pound and blueberries for $4 per pound. The farmer's goal is to make

Sergio [31]

The answer is
$2c + 4b \geqslant 500$
the key word here was at least, which means the farmer wants to make the equal or more than $500. Since the corn cost $2 and its selling per pound, depending on how many pound of corn (c) and the blueberries per pound (b) which are $4, leading to the first part of the inequality.

6 0

2 years ago

Lim x->pi/3 ((2cosx-1)/(tan^2x-3))

beks73 [17]

You can check that the limit comes in an undefined form:

$\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\dfrac{0}{0}$

In these cases, we can use de l'Hospital rule, and evaluate the limit of the ratio of the derivatives. We have:

$\dfrac{\text{d}}{\text{d}x}2\cos(x)-1 = -2\sin(x)$

and

$\dfrac{\text{d}}{\text{d}x}\tan^2(x)-3 = 2\dfrac{\tan(x)}{\cos^2(x)}=\dfrac{2\sin(x)}{\cos^3(x)}$

So, we have

$\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\lim_{x\to\frac{\pi}{3}} \dfrac{-2\sin(x)}{\frac{2\sin(x)}{\cos^3(x)}}=\lim_{x\to\frac{\pi}{3}}-\cos^3(x)=-\cos^3\left(\dfrac{\pi}{3}\right)$