Determine the value of y, if x is −8. y=x 2 +4

Mathematics

1 answer:

Alinara [238K]1 year ago

3 0

Step-by-step explanation:

given: x = -8,

putting value of x in given equation,

y=(-8)2+4

y= -16+4

y=-12

You might be interested in

Can someone help me with this or give me a link to the answers please

lana [24]

sorry it can't fit the other half

5 0

2 years ago

Graph 2x-5=2x+8 please

lapo4ka [179]

2x-5=2x+8
-5=8

y=2x-5
y=2x+8

4 0

3 years ago

Which is a unit rate?

yulyashka [42]

Answer:

3 cookies/bag

Step-by-step explanation:

First of all, let's define a unit rate. A unit rate is a ratio of the amount of one measurement to one unit of another measurement term. Unit rates can be expressed as fractions.

Now, here is something easier for you to remember: <u>the second unit always have to be something with the quantity of 1</u>.

In this case, "3 cookies/bag" shows how there are three cookies per, or in each bag--which means 1 bag. The second unit, which is bag, has the quantity of one.

6 0

2 years ago

How can caregivers give children self confidence safely?

Ann [662]

Telling them that no mater what they should love them for who they are love your self no matter what

8 0

2 years ago

A person invests $4000 at 2% interest compounded annually for 4 years and then invests the balance (the $4000 plus the interest

faltersainse [42]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4000\\
r=rate\to 2\%\to \frac{2}{100}\to &0.02\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}
\\\\\\
A=4000\left(1+\frac{0.02}{1}\right)^{1\cdot 4}\implies A=4000(1.02)^4\implies A\approx 4329.73$

then she turns around and grabs those 4329.73 and put them in an account getting 8% APR I assume, so is annual compounding, for 7 years.

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$4329.73\\
r=rate\to 8\%\to \frac{8}{100}\to &0.08\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &7
\end{cases}
\\\\\\
A=4329.73\left(1+\frac{0.08}{1}\right)^{1\cdot 7}\implies A=4329.73(1.08)^7\\\\\\ A\approx 7420.396$

add both amounts, and that's her investment for the 11 years.

7 0

2 years ago