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mylen [45]
3 years ago
5

How to find the line of best fit

Mathematics
1 answer:
8090 [49]3 years ago
7 0

Answer:

depends on the graph and equation but find 2 points and draw the line from there also find the slope so you can see (when you add more points) if they match up to your line  

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Dara has to solve 35 math problems for homework. She has completed 14 of them.what fraction of the problems does she have left t
RSB [31]

Answer: 3/5

Step-by-step explanation: thats your answer.

6 0
3 years ago
Find the product of <br><br><br><br> <img src="https://tex.z-dn.net/?f=8%284%5Csqrt%207-%5Csqrt18%29" id="TexFormula1" title="8(
Eduardwww [97]

Answer:

Distribute

Step-by-step explanation:

8*4sq7 and 8*sq of 18

6 0
2 years ago
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Can somebody pls help​
Delvig [45]
The answer is A domain
6 0
3 years ago
Chandra created a budget matrix based on her regular and expected expenses for the year. Expense Jan. Feb. Mar. Apr. May June Ju
Ivan

Answer:

Chandra's Average Monthly Expenses are;

1) For Both Jan and Feb are $269

2) For the remaining 10 months each are $244

Step-by-step explanation:

From Chandra's matrix all monthly expenses are all same that is,

Cell phone $71, Rent $1,025, Gym $75, Internet $25, Auto insurance $425, Gas $ 120, Food $145. which are all the expenses carried out every month for 12 months.

That means Chandra carries out a total of 7 expenses for the month of January and February while she carried a total of 6 expenses for the remaining 10 month which was noted from the matrix that Auto insurance was carried out only in the month of January and February.

Therefore, you start by adding up each month total expenses, which are ;

January = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

February = $71 + $1,025 + $75 + $25 + $425 + $120 + $145 = $1886

March = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

April = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

May = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

June = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

July= $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

August = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

September = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

October = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

November = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

December = $71 + $1,025 + $75 + $25  + $120 + $145 = $1461

Therefore Chandra's Average Monthly Expenses are:

1) January & February  = \frac{71 + 1,025 + 75 + 25 + 425 + 120 + 145}{7} = \frac{1886}{7} = 269.4286 to the nearest cent

≅ $269

2) For the remaining 10 month are = \frac{71 + 1,025 + 75 + 25  + 120 + 145}{6} = \frac{1461}{6}= 243.5 to the nearest cent

≅ $244

8 0
3 years ago
Read 2 more answers
This graph displays a linear function. Interpret the constant rate of change of the relationship.
IgorC [24]

Answer: -3/-1  or 3/1 is the rate of change

Step-by-step explanation:

(0,2)

(3,3)    0-3==-3  

          2-3= -1  

-3/-1

4 0
4 years ago
Read 2 more answers
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