Let the initial count of his fish be n.
He gives away 2/3 of these fish: 2n/3, leaving n/3 fish.
He gives away 2/5 of these remaining n/3 fish: (2/5) times (n/3), or
2n
--- , meaning that (3/5) times (n/3) fish are left.
15
(3/5)(n/3) = n/5 fish left = 30 fish. Thus, n = 150 fish.
Be certain to check this answer!
Answer:
q=−3x3+4x2−x
hope this helped :)
Step-by-step explanation:
Answer:
ok ask the question plzzzzz
Answer: A= s^2 <- for a square
A= 1/2*b*h <- for a triangle
A= 4^2= 16
A= 1/2*8*6 (The whole height is 8 yd)
A= 1/2*48
A= 24
24+16= 40 yd^2
"B" is the answer.
I hope this helps!
Step-by-step explanation: A= s^2 <- for a square
A= 1/2*b*h <- for a triangle
A= 4^2= 16
A= 1/2*8*6 (The whole height is 8 yd)
A= 1/2*48
A= 24
24+16= 40 yd^2
"B" is the answer.
I hope this helps!
