2 0

Question 3 (1 point)

Sindrei [870]

Answer:

96

Step-by-step explanation:

(3+6+3)•9-(3•2)-(3•2)

12•9-6-6

=108-12

=96

3 0

3 years ago

In ADEF, m must be true?<br> Plssss need helpppp

Rzqust [24]

Answer:

E. FD<DE<EF

Step-by-step explanation:

First I needed to find the other angle which I found by adding the two angles that were given.

103 +14 =117

180 - 117= 63

then to find which sides were the longest I looked and the angles and found their corresponding sides.

<D went with side FE

<F went with side DE

<E went with side FD

The smallest angle was <E therefore the smallest side was FD

The middle angle was <F therefore the medium side was DE

The largest angle was <D therefore the smallest side was FE

I hope this helps!!

Please tell me if I have made a mistake enjoy learning from them!!

If I am correct could you please mark me brainliset? I am trying to level up!!

Thank you for your time:)

5 0

3 years ago

Find the roots. 2x 2 + 7x - 15 =0

Reika [66]

So you always want to pull out the gcf first but since there isn't one, we can move on.
so we can make an acb chart which is multiplying the a value and the c value and find factors that of that product that will equal the b value.
a value is 2
c value is -15
b value is 7
-30 factors to equal 7 = 10, -3
10 - 3 = 7
so the factors 10 and -3 work.
so now you make 2 separate parenthesis with one of the factors and one x. and it should be set equal to 0.
(x+10)(x-3) = 0
now solve for x in each separate parenthesis.
x = -10
x = 3
those r the roots
hope this helps

4 0

3 years ago

Read 2 more answers

Find the value of :<br><img src="https://tex.z-dn.net/?f=%20%5Csf%20log_%7B3%20%5Csqrt%7B2%7D%20%7D%28324%29%20" id="TexFormula1

qwelly [4]

Answer:

4

Step-by-step explanation:

Is that a log with the base of 3√(2) ?

If so....my calculator says the answer is 4

Let's see if we can do it w/ou the calculator:

3 sqrt(2)^x = 324 = 3^4 * 2^2 Now 'LOG' both sides:

x log (3 sqrt 2) = log (3^4 *2^2) = 4 log ( 3 * 2^(2/4)) = 4 log (3 sqrt2)

now divide both sides by log (3 sqrt2 )

x = 4 (If I did the math correctly ! )

8 0

2 years ago

A random sample of 25 ACME employees showed the average number of vacation days taken during the year is 18.3 days with a standa

Norma-Jean [14]

Answer:

a) Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

b) $df=n-1=25-1=24$

For this case the p value is given $p_v = 0.0392$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.

c) Type I error, also known as a “false positive” is the error of rejecting a null hypothesis when it is actually true. Can be interpreted as the error of no reject an alternative hypothesis when the results can be attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

Step-by-step explanation:

Data given and notation

$\bar X=18.3$ represent the sample mean

$s=3.72$ represent the sample standard deviation

$n=25$ sample size

$\mu_o =15$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a: State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean for vacation days is higher than 15, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Part b: P-value and conclusion

The first step is calculate the degrees of freedom, on this case:

$df=n-1=25-1=24$

For this case the p value is given $p_v = 0.0392$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.

Part c

Type I error, also known as a “false positive” is the error of rejecting a null hypothesis when it is actually true. Can be interpreted as the error of no reject an alternative hypothesis when the results can be attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

3 0

3 years ago