Which expression is equivalent to 0.2n +2n+4 a- 2.2n+4 b-6.2n c-4n+4 d- 2.2(n+4)

Help please!!!!!! Thank you

ivolga24 [154]

Answer:

1/4

Step-by-step explanation:

Well see how far each points are from each other.

Start at the red triangle and go up 1, go to the right 4.

Thus,

the rise/run is 1/4.

Hope this helps :)

7 0

3 years ago

Read 2 more answers

PLEASE HELP I WILL MARK BRAINLIEST AND GIVE EXTRA POINTS

xxMikexx [17]

Answer:

45 $cm^{2}$

sorry if it is not what u needed

5 0

2 years ago

Evaluate the double integral.

Fynjy0 [20]

Answer:

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

Step-by-step explanation:

The equation of the line through the point $(x_o,y_o)$ & $(x_1,y_1)$ can be represented by:

$y-y_o = m(x - x_o)$

Making m the subject;

$m = \dfrac{y_1 - y_0}{x_1-x_0}$

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

$m= \dfrac{2-1}{1-0}$

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

$m = \dfrac{1-2}{4-1}$

$m = \dfrac{-1}{3}$

∴

$y-2 = -\dfrac{1}{3}(x-1)$

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

$\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg) dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ([y^2(-4y+8)] \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \int^2_1 \bigg ( -4y^3+8y^2 \bigg ) \ dy$

$\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1$

$\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{-45+56}{3}\bigg]$

$\iint_D 8y^2 \ dA =8 \bigg [ \dfrac{11}{3}\bigg]$

$\iint_D 8y^2 \ dA = \dfrac{88}{3}$

4 0

2 years ago

A paper company needs to ship paper to a large printing business. The paper will be shipped in small boxes and large boxes. The

Delvig [45]

10 small boxes and 11 large boxes were shipped.

Step-by-step explanation:

Given,

Total boxes shipped = 21

Total volume of shipped boxes = 342 cubic feet

Volume of each small box = 10 cubic feet

Volume of each large box = 22 cubic feet

Let,

Number of small boxes = x

Number of large boxes = y

According to given statement;

x+y=21 Eqn 1

10x+22y=342 Eqn 2

Multiplying Eqn 1 by 10

$10(x+y=21)\\10x+10y=210\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(10x+22y)-(10x+10y)=342-210\\10x+22y-10x-10y=132\\12y=132$

Dividing both sides by 12

$\frac{12y}{12}=\frac{132}{12}\\y=11$

Putting y=11 in Eqn 1

$x+11=21\\x=21-11\\x=10$

10 small boxes and 11 large boxes were shipped.

Keywords: linear equation, subtraction

Learn more about linear equations at:

#LearnwithBrainly

3 0

3 years ago

What is the slope of the line with equation y=-x

zmey [24]

The slope intercept form is y=mx+b
in this case y=-x
y=(-1)x + 0
so the slope m=-1 and y-intercept which is b is 0

6 0

3 years ago

Which expression is equivalent to 0.2n +2n+4a- 2.2n+4b-6.2nc-4n+4d- 2.2(n+4)