Which table best classifies the following numbers as rational and irrational?

Which of the following equations corresponds to the graph below

alekssr [168]

the answer would be d because it goes down 2 and over 1

3 0

3 years ago

Read 2 more answers

How to work this out in geometry form?

weeeeeb [17]

B x H divided by 2 i think

8 0

3 years ago

4

Maru [420]

First, we have to understand the slope-intercept form.

$\large \boxed{y = mx + b}$

A linear function/equation has three forms and the slope-intercept is one of the form. It is also commonly used in Function topic while the other two forms are commonly used in Analytic Geometry.

In the slope-intercept form, the m-term represents the slope while b-term represents the y-intercept of a graph.

Which equation represents a linear function that has a slope of 5 and a y-intercept of -6.

As you notice the bold, italic and underlined words in the question that I quoted or rewrote. I've just explained that the slope is m-term and y-intercept is b-term.

Therefore, substitute m = 5 and b = -6 in the equation.

$\large{y = mx + b \longrightarrow \bold{y = 5x + ( - 6)}} \\ \large \boxed{ \tt{ \purple{y = 5x - 6}}}$

I hope this helps! Let me know if you have any questions regarding the linear function, don't hestitate to ask. Good luck with your assignment and have a nice day!

5 0

3 years ago

Please, I need help in this ??

nignag [31]

Answer:

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

Step-by-step explanation:

$\int\frac{x^{4}}{x^{4} -1}dx$

Adding and Subtracting 1 to the Numerator

$\int\frac{x^{4} - 1 + 1}{x^{4} -1}dx$

Dividing Numerator seperately by $x^{4} - 1$

$\int 1 + \frac{1}{x^{4}-1 }\, dx$

Here integral of 1 is x +c1 (where c1 is constant of integration

$x + c1 + \int\frac{1}{(x-1)(x+1)(x^{2}+1)}\, dx$ ----------------------------------(1)

We apply method of partial fractions to perform the integral

$\frac{1}{(x-1)(x+1)(x^{2}+1)}$ = $\frac{A}{x-1} + \frac{B}{x+1} + \frac{C}{x^{2} + 1}$ ------------------------------------------(2)

$\frac{1}{(x-1)(x+1)(x^{2}+1)} = \frac{A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)}{(x-1)(x+1)(x^{2} +1)}$

1 = $A(x+1)(x^{2} +1) + B(x-1)(x^{2} +1) + C(x-1)(x+1)$ -------------------------(3)

Substitute x= 1 , -1 , i in equation (3)

1 = A(1+1)(1+1)

A = $\frac{1}{4}$

1 = B(-1-1)(1+1)

B = $-\frac{1}{4}$

1 = C(i-1)(i+1)

C = $-\frac{1}{2}$

Substituting A, B, C in equation (2)

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\int\frac{1}{4(x-1)} - \frac{1}{4(x+1)} -\frac{1}{2(x^{2}+1) }$

On integration

Here $\int \frac{1}{x}dx = lnx and \int\frac{1}{x^{2}+1 } dx = arctanx$

$\int\frac{x^{4}}{x^{4} -1}dx$ = $\frac{1}{4} ln(x-1)$ - $\frac{1}{4} ln(x+1)$ - $\frac{1}{2} arctanx$ + c2---------------------------------------(4)

Substitute equation (4) back in equation (1) we get

$x + c1 + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1) - \frac{1}{2} arctanx + c2$

Here c1 + c2 can be added to another and written as c

Therefore,

$\int\frac{x^{4}}{x^{4} -1}dx = x + \frac{1}{4} ln(x-1) - \frac{1}{4} ln(x+1)-\frac{1}{2} arctanx + c$

4 0

3 years ago

Helppppppppppppppppppppppppppp

Paul [167]

Answer:

20, and 26 are the middle - 23 is the average. Your answer is 23.

Step-by-step explanation:

So since they are in order from least to greatest, basically it's the middle one.

Since there is an even number and there isn't a middle one (like it is here) then, it is the average of the middle two.

6 0

3 years ago