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3 years ago

Write the equation of the line that passes through (3, -2) and has a slope of 4 in point slope form

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

6 0

y = mx + b is the equation of a line;

m = slope , b = y-intercept

m = 4 : so we have : y = 4 x +b

We are give a set of points which it passes through, we can simply plug them in:

-2 = 4(3) + b (3 is the x and -2 is the y)

Then: -2 = 12 +b -14 = b

The final equation is : y = 4 x - 14

The answer is: y = 4 x - 14

I hope this helps have a fantastic day!!

diamong [38]3 years ago

4 0

y=mx+b is the equation of a line;

m=slope , b= y-intercept

m=4 ; so we have : y=4x+b

We are give a set of points which it passes through, we can simply plug them in:

-2 = 4(3)+b (3 is the x and -2 is the y)

We get -2 = 12 +b .... -14=b

our final equation is : y=4x-14

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What is the answer to 6/2(1+3)?

Kaylis [27]

Use PEMDAS to figure out which expression to work out first:

Parentheses
Exponents
Multiplication/Division
Addition/Subtraction

First, we'll want to solve the term with parentheses:

$2(1+3) = 2(4) = 2 \times 4 = 8$

The equation should now look like this:

$6 \div 8$

Divide to get your answer:

$6 \div 8 = 0.75$

The answer is 0.75.

4 0

3 years ago

To approximate the length of a lake, a surveyor starts at one end of the lake and walks 245 yards. He then turns 110 and walks 2

kolezko [41]

Answer:

Surveying To approximate the length of a marsh, a surveyor walks 250 meters from point to point , then turns and walks 220 meters to point (see figure). Approximate the length of the marsh.

hope it helped

Step-by-step explanation:

8 0

2 years ago

Please help me answer this using systems of equations with elimination.

Triss [41]

-5x+13y=-7
5x+4y=24
add the equation to eliminate x:
13y+4y=-7+24
17y=17
solve for y:
17/17y=17/17
y=1
then plug in y into any equation to solve for x:
-5x+13y=-7, y=1
-5x+(13*1)=-7
-5x+13-13=-7-13
-5x=-20
-5/-5x=-20/-5
x=4
the answers are x=4, y=1

3 0

3 years ago

Line segmentAB has vertices A(−3, 4) and B(1, −2) . A dilation, centered at the origin, is applied to AB⎯⎯⎯⎯⎯ . The image has ve

zysi [14]

Answer:

The scale factor is

$\frac{1}{3}$

Step-by-step explanation:

Line segmentAB has vertices A(−3, 4) and B(1, −2) .

A dilation, centered at the origin, is applied to AB. The image has vertices

A'(-1,4/3) and B′(1/3, −2/3) .

We know the rule for dilation by scale factor of k, is

$(x,y)\to(kx,ky)$

This means that;

$A(-3,4)\to A'(-3k,4k)$

But we know, A' has coordinates (-1,4/3)

This means that

$- 3k = - 1$

$k = \frac{1}{3}$

We could also compare:

4k=4/3

Which gives

k=⅓

5 0

3 years ago

Read 2 more answers

If f(x) = 6 – 5x and g(x) = 4x – 1, evaluate f(x) – g(x) for x = –2.

pogonyaev

Hello :
<span>f(x) = 6 – 5x and g(x) = 4x – 1
f(x)-g(x) = 6-5x-(4x-1) = 6-5x-4x+1 = -9x+7
whene x = - 2
f(x)-g(x) = -9(-2)+7 = 25......(answer : D)</span>

6 0

3 years ago