All categories

4 years ago

3x - 8y = 29

Mathematics

1 answer:

ICE Princess25 [194]4 years ago

8 0

Answer:

The best estimate for the solution is the point (0.5,-3.5)

Step-by-step explanation:

we have

-----> equation A

-----> equation B

we know that

The solution of the system of equations is the intersection point both graphs

Using a graphing tool

The intersection point is

see the attached figure

therefore

The solution of the system of equations is the point

The best estimate for the solution is the point

You might be interested in

ILL MARK YOU BRAINLIEST Which does NOT describe m - 5? *

Oduvanchick [21]

Answer:

3, m less than 5

Step-by-step explanation:

5 0

3 years ago

The range of the function f(x) = x + 5 is {7, 9}. What is the function’s domain?

Rashid [163]

If y is 7, x is 2. If y is 9, x is 4. Therefore the domain is {2,4}

5 0

3 years ago

Saed has some money.

AveGali [126]

Answer is 40

18 +14+8=40

7 0

2 years ago

A new, simple test has been developed to detect a particular type of cancer. The test must be evaluated before it is used. A med

g100num [7]

Answer:

0.3333 = 33.33% probability of a randomly chosen person not having cancer given that the test indicates cancer

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Test indicates cancer.

Event B: Person does not have cancer.

Probability of a test indicating cancer.

98% of 2%(those who have).

1% of 100 - 2 = 98%(those who do not have). So

$P(A) = 0.98*0.02 + 0.01*0.98 = 0.0294$

Probability of a test indicating cancer and person not having.

1% of 98%. So

$P(A \cap B) = 0.01*0.98 = 0.0098$

What is the probability of a randomly chosen person not having cancer given that the test indicates cancer?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0098}{0.0294} = 0.3333$

0.3333 = 33.33% probability of a randomly chosen person not having cancer given that the test indicates cancer

3 0

3 years ago

The following statement is an example of: every fall there have been hurricanes in the tropics. Therefore, there will be hurrica

Aneli [31]

Answer:

Deductive reasoning

Step-by-step explanation:

Here, we want to know the kind of reasoning the statement is.

In this question, the kind of reasoning is deductive

In the deductive reasoning type, we go from general cases to specific cases

It is just like saying the reason why there will be hurricanes in the tropics this fall is because there is an hurricane every fall

So we have gone from a general case to give a specific case

8 0

3 years ago