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3 years ago

8h = 48 can yiu please solve this

2 answers:

8 0

What it is asking is 8 times what equals 48. The best way to do this is by doing the opposite operation. 48 divided by 8 equals 6. Then if you put it in the other way you get 8(6)=48 which works out. So the answer is 6.

ohaa [14]3 years ago

3 0

If you divide 48 by 8 you will get 6 and if you multiply 8 and 6 you will get 48 so the answer is 6

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Answer:

Yes, No, Yes

Step-by-step explanation:

<u>Use the Pythagorean theorem:</u>

a² + b² = c²

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3 years ago

25 POINTS HURRY Brainliest!!!

Alborosie

I think the answer is B

7 0

3 years ago

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HELP MEEE PLS recipe cslls for 2 cups of suger and makes 48 cookies recipe B calls for 3 cups of suger and makes 54 of the same

JulijaS [17]

Answer:

So, when we solve for x we see that we can make 16 cookies using 1 cup of sugar. Then, yes, as you suggested we could divide 30 cookies by this ratio to see that we need less than 2 cups of sugar to make 30 cookies: And, as you said, this value is less than 2 cups, the value under Quantity B. Good job! I hope this helps :)

Step-by-step explanation:

5 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago

Ginger buys lunch at school every day. She always gets

shepuryov [24]

Answer:

The estimated probability that Ginger will eat a a pizza everyday of the week is;

D. 8/10 = 80%

Step-by-step explanation:

The given parameters are;

The frequency with which Ginger buys launch = Everyday

The percentage of the time the cafeteria has pizza out = 80%

The outcome of 0 and 1 = No pizza available

The outcome of 2, 3, 4, 5, 6, 7, 8, and 9 = Pizza available

Therefore, we have the;

Group number ${}$ Percentage of time pizza available

1 ${}$ 80%

2 ${}$ 80%

3 ${}$ 80%

4 ${}$ 80%

5 ${}$ 40%

6 ${}$ 100%

7 ${}$ 80%

8 ${}$ 100%

9 ${}$ 80%

10 ${}$ 80%

Therefore, the sum of the percentages outcome the days Ginger eats pizza = 0.8 + 0.8 + 0.8 + 0.8 + 0.4 + 1 + 0.8 + 1 + 0.8 + 0.8 = 8

The number of runs of simulation = 10 runs

The estimated probability that Ginger will eat a a pizza everyday of the week = (The sum of the percentages outcome the days Ginger eats pizza)/(The number of runs of simulation)

∴ The estimated probability that Ginger will eat a a pizza everyday of the week = 8/10

6 0

3 years ago

Read 2 more answers