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lubasha [3.4K]
3 years ago
13

Given the int variables x, y, and z, write a fragment of code that assigns the smallest of x, y, and z to another int variable m

in. Assume that all the variables have already been declared and that x, y, and z have been assigned values.
Computers and Technology
1 answer:
Marysya12 [62]3 years ago
6 0

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int x=5,y=2,z=9;

   int min;

   // find the smallest value and assign to min

   // if x is smallest

   if(x < y && x < z)

   // assign x to min

    min=x;

     // if y is smallest

else if(y < z)

 // assign y to min

    min=y;

// if z is smallest

else

 // assign z to min

    min=z;

// print the smallest

cout<<"smallest value is:"<<min<<endl;

return 0;

}

Explanation:

Declare and initialize variables x=5,y=2 and z=9.Then check if x is less than y and x is less than z, assign value of x to variable "min" .Else if value of y is less than value of z then smallest value is y, assign value of y to "min".Else z will be the smallest value, assign its value to "min".

Output:

smallest value is:2

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1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the fi
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Answer:

Explanation:

1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.  

  double alpha[50];

   for (int i=0;i<25;i++)

   {

       alpha[i]=i*i;

       alpha[i+25]=(i+25)*3;

  }

2. Output the array so that exactly ten elements per line are printed.  

   for (int i=0;i<50;i++)

   {

       cout<<i+1<<". "<<alpha[i]<<" ";

       if (((i+1)%10)==0)

       {

           cout<<endl;

       }

   }

3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.  

   double alpha[50];

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

   }

   for (int i=0;i<50;i++)

   {

       cout<<i+1<<". "<<alpha[i]<<" ";

       if (((i+1)%10)==0)

       {

           cout<<endl;

       }

   }

4. Write the code that computes and prints the average of elements of the array.  

   double alpha[50],temp=0;

   for (int i=0;i<50;i++)

   {

       alpha[i]=rand()%101;

       temp+=alpha[i];

   }

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5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.

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   for (int i=0;i<50;i++)

   {

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       {

           temp++;

       }

   }

   cout<<"Elements Exacctly 100 :"<<temp;

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#include <iostream>

using namespace std;

int main()

{

   // If you put  each of above code here it will run perfectly after compiling

   return 0;

}

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