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harina [27]
3 years ago
15

7Bx%20%7B%7D%5E%7B2%7D%20%20-%207x%20%2B%2010%7D%20" id="TexFormula1" title=" \frac{3x}{x {}^{2} - 3x - 10 } - \frac{6x}{x {}^{2} - 7x + 10} " alt=" \frac{3x}{x {}^{2} - 3x - 10 } - \frac{6x}{x {}^{2} - 7x + 10} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0
\bf \cfrac{3x}{x^2-3x-10}-\cfrac{6x}{x^2-7x+10}\implies \cfrac{3x}{(x-5)(x+2)}-\cfrac{6x}{(x-5)(x-2)}
\\\\\\
\textit{our LCD is clearly then }(x-5)(x+2)(x-2)
\\\\\\
\cfrac{(x-2)3x~~-~~[(x+2)6x]}{(x-5)(x+2)(x-2)}\implies \cfrac{3x^2-6x~~-~~[6x^2+12x]}{(x-5)(x+2)(x-2)}
\\\\\\
\cfrac{3x^2-6x-6x^2-12x}{(x-5)(x+2)(x-2)}\implies \cfrac{-3x^2-18x}{(x-5)(x+2)(x-2)}
You might be interested in
Amelia wants to paint three walls in her family room. Two walls are 26 feet long by 9 feet wide. The other wall is 18 feet long
sattari [20]
Given:
Wall 1 & 2 : 26 ft by 9 ft
Wall 3 : 18 ft by 9 ft

Area 1 : 26 ft x 9 ft = 234 ft²
Area 2 : 26 ft x 9 ft = 234 ft²
Area 3 : 18 ft x 9 ft = 162 ft²

Total Area : 234 ft² + 234 ft² + 162 ft² = 630 ft²

1 Gallon = 250 ft²

630 ft² ÷ 250 ft² per gallon = 2.52 gallons
6 0
3 years ago
jada can write 3 1/4 pages in 8 minutes. At this rate, how many pages could jada write in 24 minutes?
makkiz [27]

Answer:

9  3/4  pages = x    

Step-by-step explanation:

\frac{pages}{minutes} = \frac{pages}{minutes}        change 3 1/4 to a decimal

\frac{3.25}{8} = \frac{x}{24}

3.25(24) = 8x

78 = 8x

\frac{78}{8} = x

9.75 = x  

9\frac{3}{4} =x

working with the fraction

3 1/4 /8 = x/ 24

3 1/4 (24) = 8x            

 13/4 (24) = 8x

  316/4 = 8x

  78 = 8x

78/8 = x

9 3/4 = x

7 0
2 years ago
Jacob leaves his summer cottage and drives home. After
krok68 [10]

Answer:

A linear relationship can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If this line passes through the points (a, b) and (c, d) then the slope can be written as:

a = (a - c)/(b - d)

Here y will represent the distance between Jacob and his house, and the variable x represents the time that he has ben driving.

In this case, we know that after driving for 5 hours, he is 112km from home.

Then we can write this point as (5h, 112km)

We also know that after 7 hours he is 15km from home.

Then we can write this point as (7h, 15km)

Then the slope of this function will be:

a = (15km - 112km)/(7h - 5h) = -48.5 km/h

Then the equation is:

y = -(48.5 km/h)*x + b

To find the value of b, we can replace the values of one of the points, for example in the point (7h, 15km)

This means that we need to replace x by 12h, and y by 15km, then we get:

15km = -( 48.5 km/h)*7h + b

15km + ( 48.5 km/h)*7h = b = 354.5 km

then the equation will be:

y = (-48.5 km/h)*x + 354.5 km

Now we want to answer: How long had Jacob been driving when he was 209 km from  home?

Then we need to only replace y by 209km, and solve for x:

209km = (-48.5 km/h)*x + 354.5 km

209km - 354.5 km = (-48.5 km/h)*x

-145.5km =  (-48.5 km/h)*x

-145.5km/( -48.5 km/h) = x = 3h

So he is 209km away from his home after driving for 3 hours.

6 0
3 years ago
PLEASE HELP ME WITH THIS MATH!!!!!!!!!. pLeAsE i ReAlLy NeEd SoMe HeLp
KonstantinChe [14]
Part 1) we know that
m∠5=44°    m∠11=86°
m∠2=m∠5------> by vertical angles
m∠2=44°
m∠13=m∠11------> by vertical angles
m∠13=86°
m∠12+m∠13=180°-----> supplementary angles
m∠12=180-86-----> m∠12=94°
m∠14=m∠12----> by vertical angles
m∠14=94°
m∠1=m∠11----> by corresponding angles
m∠1=86°
m∠4=m∠1----> by vertical angles
m∠4=86°
m∠2+m∠1+m∠6=180
m∠6=180-(86+44)----> 50°
m∠6=50°
m∠3=m∠6----> by vertical angles
m∠3=50°
m∠8=m∠3----> by corresponding angles
m∠8=50°
m∠8+m∠7=180°-----> supplementary angles
m∠7=180-50----> 130°
m∠7=130°
m∠10=m∠6----> by corresponding angles
m∠10=50°
m∠10+m∠9=180°-----> supplementary angles
m∠9=180-50-----> 130°
m∠9=130°

the answers Part 1) are
m∠1=86°
m∠2=44°
m∠3=50°
m∠4=86°
m∠5=44° 
m∠6=50°
m∠7=130°
m∠8=50°
m∠9=130°
m∠10=50°
m∠11=86°
m∠12=94°
m∠13=86°
m∠14=94°

Part 2) 
a) what is m∠TPR?
in the right triangle PTR 
m∠PTR+m∠TPR+m∠TRP=180° ( the sum of internal angles of triangle is equal to 180 degrees)
m∠PTR=30°
m∠TRP=90°
so
m∠TPR=180-(90+30)----> 60°

the answer Part 2a) is 
m∠TPR=60°

b) what is the length in inches of segment PR?
in the right triangle PTR 
sin 30=PR/TP-----> PR=TP*sin 30-----> PR=14*(1/2)----> 7 in

the answer Part 2b) is
PR=7 in

c)  what is the length in inches of segment TR?
in the right triangle PTR 
cos 30=TR/PT-----> TR=PT*cos 30-----> TR=14*(√3/2)---> TR=7√3 in

the answer Part 2c) is
TR=7√3 in

d)  what is the length in inches of segment PQ?
in the right triangle PQR
PR=7 in
RQ=PR-----> by angle 45°
so
RQ=7 in
applying the Pythagoras Theorem
PQ²=RQ²+PR²-----> 7²+7²-----> PQ²=98-----> PQ=√98 in---> PQ=7√2 in

the answer Part 2d) is
PQ=7√2 in

Part 3) Patrice buys a block of wax in the shape of a right rectangular prism. The dimensions of the block are 20 cm by 9 cm by 8 cm.
  <span><span>(a)   </span>What is the volume of the block?

volume of the prism=20*9*8-----> 1440 cm³

the answer Part 3 a) is
the volume of the block is 1440 cm³
<span>
Patrice melts the wax and creates a candle in the shape of a circular cylinder that has a diameter of 10 cm and a height of 15 cm.<span>(b)   </span>To the nearest centimeter, what is the volume of the candle?
</span></span>volume of a cylinder=pi*r²*h
diameter=10 cm
radius r=10/2----> 5 cm
h=15 cm
volume of a cylinder=pi*5²*15----> 1177.5 cm³-----> 1178 cm³

the answer Part 3b) is
the volume of the candle is 1178 cm³

<span>Patrice decides to use the remaining wax to create a candle in the shape of a cube.<span>(c)   </span>To the nearest centimeter, what is the length of the side of the cube?
</span>
the remaining wax=volume of the prism-volume of a cylinder
=1440-1178-----> 262 cm³

volume of a cube=b³
where b is the length side of the cube
262=b³-------b=∛262-----> b=6.40 cm-----> b=6 cm

the answer Part 3c) is
the length of the side of the cube is 6 cm
5 0
3 years ago
If x = -5 <br><br> x2 + 3<br> x - 2
MAXImum [283]

Answer:

Step-by-step explanation:

8 0
3 years ago
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