Answer:
Triangles ABE and CDE are congruent by AAS.
Step-by-step explanation:
AB ≅ DC (Opposite sides of a parallelogram are congruent.
m < AEB = m < DEC (Vertical angles).
m < ABE = m < EDC ( Alternate Interior angles).
So triangles ABE and CDE are congruent by AAS.
You can find the remainder right away by simply plugging in

. The polynomial remainder theorem guarantees that the value of

is the remainder upon dividing

by

, but I digress...
Synthetic division yields
3 | 2 -11 18 -15
. | 6 -15 9
- - - - - - - - - - - - - - - - -
. | 2 -5 3 -6
which translates to

(and note that

, as expected)
6............................................
Answer:
Step-by-step explanation:
<u>Given points</u>
<u>Slope-intercept form</u>
<u>Slope of the line is</u>
- m = (6a - 2a)/( -5a - a) = 4a/(-6a) = - 2/3
<u>The y-intercept is:</u>
- 2a = -2/3*a + b
- b = 2a + 2/3a
- b= 8/3a
<u>So the line is:</u>
If you mean the m^3=105, then m^6 will be
![( \sqrt[3]{105}) ^6](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B3%5D%7B105%7D%29%20%5E6)
which is 105^2 which is
11025