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Aleksandr [31]
4 years ago
14

Is the ratio 4.2:1.5 proportional to the ratio 12.6:4.5? Explain. PLEASE HELP I SUCK AT MATH!!!!

Mathematics
2 answers:
Lana71 [14]4 years ago
7 0

Yes, the two ratios are proportional to each other. The multiplier from the first ratio to the second ratio is 3. For example, 4.2 x 3 = 12.6 and 1.5 x 3 = 4.5. Basically, to figure out if two ratios are proportional to each other, just divide the smaller number into the bigger number for both corresponding numbers. If they're the same ---> Proportional. If they're not the same ---> Not Proportional
zepelin [54]4 years ago
6 0
Yes it is  proportional because the ratios are related in the physics.
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Answer:

24 miles

Step-by-step explanation:

50 minutes = 8 miles

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2 years ago
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You need to design a rectangle with a perimeter of 14.2 cm. The length must be 2.4 cm. What is the width of the
irina1246 [14]

Part (a)

<h3>Answer: 2(2.4+w) = 14.2</h3>

--------------

Explanation:

L = 2.4 = length

W = unknown width

The perimeter of any rectangle is P = 2(L+W)

We replace L with 2.4, and replace P with 14.2 to get 14.2 = 2(2.4+w) which is equivalent to 2(2.4+w) = 14.2

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Part (b)

<h3>Answer:   w = 4.7</h3>

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Explanation:

We'll solve the equation we set up in part (a)

2(2.4+w) = 14.2

2(2.4)+2(w) = 14.2

4.8+2w = 14.2

2w = 14.2-4.8

2w = 9.4

w = 9.4/2

w = 4.7

The width must be 4.7 cm.

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3 years ago
The number of girls who work at Super shopper is 2 more than 3 times the number of boys. If 30 boys work at super shopper; how m
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Step-by-step explanation:

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Use the following matrices, A, B, C and D to perform each operation.
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Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

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3 years ago
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