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amid [387]
3 years ago
12

What is an equation of the line that passes through the point (3,-1) and is perpendicular to the equation y=-3x+2

Mathematics
1 answer:
Alex17521 [72]3 years ago
8 0
If it is perpendicular then the slope of it will be:

-3 \times x = -1\\\\x = \frac{1}{3}

y = 1/3 x + b

-1 = (1/3)(3) + b

-1 = 1 + b

b = -2

The equation is:

y = \frac{1}{3}x - 2
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Tell what you would do to isolate the variable.
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The 10th term of an a.p is -27 and the 5th term is -12 .find the first term?​
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Step-by-step explanation:

a_{10} = - 27... (Given) \\\\\therefore a + 9d = - 27...... (1)\\\\a_{5} = - 12... (Given) \\\\\therefore a + 4d = - 12.......(2)\\\\

Subtracting equation (2) from equation (1)

a + 9d-( a + 4d )= - 27-(-12)\\\\\therefore a +9d - a-4d = - 27+12\\\\\therefore 5d = - 15\\\\\therefore d = \frac {- 15}{5}\\\\\huge \orange {\boxed {\therefore d = -3}} \\\\

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3 years ago
Find vertex of f(x)=(x+3)(x-5)
astra-53 [7]

The x coordinate of the vertex will be the average of the two zeros, here -3 and 5, so x=(-3+5)/2 = 1, f(1)=(1+3)(1-5) = -16.

Answer: (1, -16)

Let's do it some other ways.  How about completing the square to turn f in to vertex form?

f(x) = (x+3)(x-5) = x² - 2x - 15 = (x² - 2x + 1) - 1 - 15 = (x-1)² - 16

and now we can read off (1, -16) as the vertex.

The other method is the vertex is x= - b/2a =  - (-2)/2(1) = 1.

Three methods, same answer. Good.

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Divide.
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Answer:

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